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Arisa [49]
3 years ago
6

Malik buys and sells car parts. He bought two tires for $45.00 each and later sold them for $65.00 each. He bought three rims fo

r $85.00 each and later sold them for $126.00 each. He bought five headlight covers for $5.00 each and later sold them for $15.00 each. What is Malik's total profit?
Mathematics
2 answers:
dybincka [34]3 years ago
7 0
2 Tires:
Cost Price = $45 x 2 = $90
Sales Price = $65 x 2 = $130
Profit  = $130 - $90 = $40

3 Rims:
Cost Price = $85 x 3 = $255
Sales Price = $126 x 3 = $378
Profit = $378 - $255 = $123

5 headlights:
Cost Price = $5 x 5 = $25
Sales Price = 15 x 5 = $75
Profit = $75 - $25 = $50

Total Profit = $40 + $123 + $50 = $213

Answer: $213
Aleksandr [31]3 years ago
3 0
Malik earned $243.

When he bought the tires, he spent $90 ($45x2), and he sold them for $130 ($65x2). So his profit was $40 ($130-$90).

He bought three rims for $225 ($85x3) and sold them all for $378 ($126x3). His profit was $153 ($378-$225).

The headlight covers cost him $25 in total ($5x5). He sold them all and got $75 ($15x5). The profit was $50 ($75-$25).

The total amount of money made was $243 ($40+$153+$50).

:)
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3 years ago
The following data on average daily hotel room rate and amount spent on entertainment (The Wall Street Journal, August 18, 2011)
Zielflug [23.3K]

Answer:

a. Predicted Amount = $109.46

b. Confidence Interval = (94.84,124.08)

c. Interval = (110.6883,188.8517)

Step-by-step explanation:

Given

ŷ = 17.49 + 1.0334x.

SSE = 1541.4

a.

ŷ = 17.49 + 1.0334(89)

ŷ = 109.4626

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Predicted Amount = $109.46

b.

ŷ = 17.49 + 1.0334(89)

ŷ = 109.4626

ŷ = 109.46

First we calculate the standard deviation

variance = SSE/(n-2)

v = 1541.4/(9-2)

v = 1541.4/7

v = 220.2

s = √v

s = √220.2

s = 14.839

Then we calculate mean(x) and ∑(x - (mean(x))²

X --- Y -- Mean(x) --- ∑(x - (mean(x))²

148 -- 161 -- 43-- 1849

96 || 105|| -9 || 81

91 ||101 || -14 || 196

110 || 142 || 5 || 25

90 || 100 || -15 || 225

102 || ||120 ||-3|| 9

136 || 167 ||31 ||961

90 || 140 ||-15 ||225

82 || 98 ||-23 || 529

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Mean (x) = 945/9 = 105

∑(x - (mean(x))² = 4100

α = 1 - 95% = 5%

α/2 = 2.5% = 0.025

tα,df = n − 2 = t0.025,7 =2.365

Confidence interval = 109.46 ± 2.365 * 14.839 √((1/9)+ (89-105)²/4100

Confidence Interval = (109.46 ± 14.62)

Confidence Interval = (94.84,124.08)

c.

ŷ = 17.49 + 1.0334(128)

ŷ = 149.7652

ŷ = 149.77

Interval = 149.77 ± 2.365 * 14.839 √((1/9)+ (128-105)²/4100

Interval = 149.77 ± 39.0817

Interval = (110.6883,188.8517)

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Answer:

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Step-by-step explanation:

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