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Arisa [49]
3 years ago
6

Malik buys and sells car parts. He bought two tires for $45.00 each and later sold them for $65.00 each. He bought three rims fo

r $85.00 each and later sold them for $126.00 each. He bought five headlight covers for $5.00 each and later sold them for $15.00 each. What is Malik's total profit?
Mathematics
2 answers:
dybincka [34]3 years ago
7 0
2 Tires:
Cost Price = $45 x 2 = $90
Sales Price = $65 x 2 = $130
Profit  = $130 - $90 = $40

3 Rims:
Cost Price = $85 x 3 = $255
Sales Price = $126 x 3 = $378
Profit = $378 - $255 = $123

5 headlights:
Cost Price = $5 x 5 = $25
Sales Price = 15 x 5 = $75
Profit = $75 - $25 = $50

Total Profit = $40 + $123 + $50 = $213

Answer: $213
Aleksandr [31]3 years ago
3 0
Malik earned $243.

When he bought the tires, he spent $90 ($45x2), and he sold them for $130 ($65x2). So his profit was $40 ($130-$90).

He bought three rims for $225 ($85x3) and sold them all for $378 ($126x3). His profit was $153 ($378-$225).

The headlight covers cost him $25 in total ($5x5). He sold them all and got $75 ($15x5). The profit was $50 ($75-$25).

The total amount of money made was $243 ($40+$153+$50).

:)
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<em>Your premise and conclusion are both incorrect</em>.

120 has the prime factorization ...

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When a number is multiplied by 2, its number of natural-number divisors will be (n+1)/n times the previous number of divisors, where n is the increment of the exponent of 2 that is a factor of the original number.

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The number of divisors of an integer is the product of the increments of the exponents of its prime factors.

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<em>For reference</em>

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