Answer:
Step-by-step explanation:
We know that the mean and the standard error of the sampling distribution of the sample proportions will be :-
, where p=population proportion and n= sample size.
Given : The proportion of students at a college who have GPA higher than 3.5 is 19%.
i.e. p= 19%=0.19
The for sample size n= 25
The mean and the standard error of the sampling distribution of the sample proportions will be :-
Hence , the mean and the standard error of the sampling distribution of the sample proportions :
I think it's A. I can't really see the graphs clearly. It's the one that crosses at (15,2)
Answer:
$883.14
Step-by-step explanation:
Have a great day! ;)
Answer:
12 x 4 or 48
Step-by-step explanation:
Let the weightage of Ease of Use be x
Ease of Use = x
<span>Compatibility is 5 times more than ease of use:
</span>Compatibility = 5x
<span>Reputation is 3 times more important than compatibility:
</span>Reputation = 3(5x)
Reputation = 15x
<span>Cost is 2 times more important than reputation:
</span>Cost = 2(15x)
Cost = 30x
So the weightage are:
Ease of Use : 1
Compatibility : 5
Reputation :15
Cost : 30