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2 years ago

Guys help me we want to hit 325 subs on yt!!!!!

Mathematics

2 answers:

Irina18 [472]2 years ago

7 0

Answer:

362880 and yes i did :)

Step-by-step explanation:

maria [59]2 years ago

6 0

Answer:

72576

is the answer

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Amy has four more 20c coins than 5c coins. The total value of all her 20c and 5c is $3.80. How many 5c coins does Amy have?

skelet666 [1.2K]

Answer:

Amy has 12 5¢ coins

Step-by-step explanation:

Let x represent 20¢ coins and y represent 5¢ coins.

Amy has four more 20¢ coins than 5¢ coins. Hence:

$x=y+4$

And the total value of all her coins is $3.80. Thus:

$0.2x+0.05y=3.8$

This yields a system of equations:

$\displaystyle \begin{cases} x=y+4 \\ 0.2x+0.05y=3.8\end{cases}$

We can solve by substitution. Substitute the first equation into the first:

$\displaystyle 0.2(y+4)+0.05y=3.8$

Distribute:

$\displaystyle 0.2y+0.8+0.05y=3.8$

Combine like terms:

$\displaystyle 0.25y = 3$

And divide both sides by 0.25. Hence:

$y=12$

Thus, Amy has 12 5¢ coins.

Using the first equation:

$x=y+4$

Substitute:

$x=(12)+4=16$

Thus, Amy has 16 20¢ coins.

In conclusion, Amy has 12 5¢ coins and 16 20¢ coins.

6 0

3 years ago

For a confidence level of 85%, find the critical value for a normally distributed variable. The sample mean is normally distribu

const2013 [10]

Answer:

The value is $Z_{\alpha } = 1.439$

Step-by-step explanation:

From the question we are told that

The confidence level is C = 85%

Generally the level of significance is mathematically represented as

$\alpha = (100 - 85 )\%$

$\alpha = 0.15$

Now from the normal distribution table the critical value of $\alpha$ is

$Z_{\alpha } = 1.439$

7 0

3 years ago

Some1 help me this due tomorrow and in stressing out

Olenka [21]

Answer:

Step-by-step explanation:

So, as shown in the picture below, you first have to find the line y = -1. Then that’s what your going to reflect. Imagine that your making a print of it, that’s how you will reflect it. Imagine taking a piece of paper with that triangle on it and folding it along that line I drew in my picture (at y=-1). Hope that helped!