Question

What is the distance between (5,7) and (11,-1)

Answer 1

Answer:

10 units

Step-by-step explanation:

To find the distance between two points on a graph, we use the distance formula $d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2$ where $d$ is the distance between points $(x_1,y_1)$ and $(x_2,y_2)$.

For this problem, we will identify $(x_1,y_1)\rightarrow(5,7)$ and $(x_2,y_2)\rightarrow(11,-1)$:

$d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}\\\\d=\sqrt{(-1-7)^2+(11-5)^2}\\\\d=\sqrt{(-8)^2+(6)^2}\\\\d=\sqrt{64+36}\\\\d=\sqrt{100}\\\\d=10$

Therefore, the distance between $(5,7)$ and $(11,-1)$ is 10 units