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cluponka [151]
3 years ago
13

Find the area of regular polygon. can anyone help me been stuck with this for hours

Mathematics
2 answers:
rewona [7]3 years ago
6 0

Answer:

Step-by-step explanation:

Area of hexagon given apothem. (The line that is 5 rad 3)

The apothem is perpendicular to the side of the hexagon, forming a triangle with the corner of the hexagon. The angle measurement of the corner is 60 degrees because the angle measurement of any interior angle of a regular hexagon is 120. this means that the imaginary triangle connecting the apothem to the closest corner and that to the center is a 30-60-90 triangle.

The sides of a 30-60-90 triangle are

a (the shortest side)= x

b (The longer leg/ apothem in this scenario)= x rad 3

c (hypotenuse)=2x

a=5

b=5 rad 3

c=10

2a= side length = 10

using the formula for hexagon area

A =((3 rad 3)/2) s^2

where s is the side

(3 rad 3)/2 x 100

A=259.81

vitfil [10]3 years ago
5 0

Answer:

The answer to your question is 259.8 cm²

Step-by-step explanation:

Formula

             Area = \frac{Perimeter x A}{2}

See the picture below

1.- Find the perimeter

From the right triangle find the lenght of one side

    tan 30° = \frac{x}{5\sqrt{3} }

    x = 5\sqrt{3} tan30°

    tan 30° = \frac{1}{\sqrt{3} }

Then

   x = 5\frac{\sqrt{3} }{\sqrt{3} }

   x = 5

  lenght of a side = 2x = 2(5) = 10

Perimeter = 10 x 6

                = 60

2.- Find the area

           Area = \frac{60 x 5\sqrt{3} }{2}

           Area = 30x5\sqrt{3}

           Area = 150\sqrt{3}

          Area = 259.8 cm^{2}    

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timurjin [86]

Answer:

2.

x³+2x²+5x+10

x²(x+2)+5(x+2)

taking common

(x+2)(x²+5) is your answer

a³-a²b²-ab+b³

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a²(a-b²)-b(a-b²)

taking common

(a-b²)(a²-b)

5 0
2 years ago
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The graphs of the function f (given in blue) and g (given in red) are plotted above. Suppose that u(x)=f(x)g(x) and v(x)=f(x)/g(
Rus_ich [418]
U(x) = f(x).(gx)
v(x) = f(x) /  g(x)

Use chain rule to find u(x) and v(x).

u '(x) = f '(x) g(x) + f(x) g'(x)

v ' (x) = [f '(x) g(x) - f(x) g(x)] / [g(x)]^2

The functions given are piecewise.

You need to use the pieces that include the point x = 1.

You can calculate f '(x) and g '(x) at x =1, as the slopes of the lines that define each function.

And the slopes can be calculated graphycally as run / rise of each graph, around the given point.

f '(x) = slope of f (x); at x = 1, f '(1) = run / rise = 1/1 = 1

g '(x) = slope of g(x); at x = 1, g '(1) = run / rise = 1.5/ 1 = 1.5

You also need f (1) = 1 and g(1) = 2

Then:

u '(1) =  f '(1) g(1) + f(1) g'(1) = 1*2 + 1*1.5 = 2 + 1.5 = 3.5

v ' (x) = [f '(1) g(1) - f(1) g(1)] / [g(1)]^2 = [1*2 -  1*1.5] / (2)^2 = [2-1.5]/4 =

= 0.5/4 = 0.125

Answers:
u '(1) = 3.5
v '(1) = 0.125

 


 

3 0
3 years ago
Could anyone prove this question correct... pls... I will mark branliest for step by step solution.
Masja [62]

Answer:

C

Step-by-step explanation:

the answer is 15. hope this helps

8 0
3 years ago
What is the following product?
KiRa [710]

ANSWER

2 \sqrt{42} +7  \sqrt{2}- 6- \sqrt{21}

EXPLANATION

The given product is:

( \sqrt{14}  -  \sqrt{3} )( \sqrt{12} +  \sqrt{7}  )

We expand using the distributive property to obtain:

\sqrt{14}( \sqrt{12} +  \sqrt{7}) -\sqrt{3}( \sqrt{12} +  \sqrt{7}  )

Extract the perfect squares to get:

\sqrt{14}(2 \sqrt{3} +  \sqrt{7}) -\sqrt{3}( 2\sqrt{3} +  \sqrt{7}  )

Expand further to get;

2 \sqrt{42} +7  \sqrt{2}- 2(3)   - \sqrt{21}

This simplifies to,

2 \sqrt{42} +7  \sqrt{2}- 6- \sqrt{21}

5 0
3 years ago
I need help with this
WITCHER [35]
What letter? Or all?
7 0
3 years ago
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