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Gnom [1K]
2 years ago
7

Daniel and Saquon are each saving money.

Mathematics
1 answer:
tangare [24]2 years ago
3 0
It would take 5 weeks for their savings accounts to be equal.

Daniel starts with $50 and each week he adds $8. To find out the amount he has in any given week, the following formula would work:
= 50 + 8x
The x is the number of weeks and is multiplied by 8 because the amount of money he has increase by 8 every week.
After 4 weeks he would have:
= 50 + (8 * 4)
= 50 + 32
= $82
Saquon
Applying the same formula:
= 65 + 5x
After 4 weeks:
= 65 + (5 * 4)
= 65 + 20
= $85
Saquon has more money after 4 weeks.
Number of weeks it would take for both of them to have the same amount.
To find this out, equate both formulas and solve for x.
50 + 8x = 65 + 5x
8x - 5x = 65 - 50
3x = 15
x = 15/3
x = 5 weeks
At 5 weeks they will both have:
50 + 8 * 5 = $90
65 + 5 * 5 = $90
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Answer:

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6 0
3 years ago
Y''-2y'+y=2(e^x)-3(e^-x)
labwork [276]
First find the characteristic solution. The characteristic equation is

r^2-2r+1=(r-1)^2=0

which as one root at r=1 of multiplicity 2. This means the characteristic solution for this ODE is

y_c=C_1e^x+C_2xe^x

For the nonhomogeneous part, you can try a particular solution of the form

y_p=(a_2x^2+a_1x+a_0)e^x+be^{-x}

which has derivatives

{y_p}'=(a_2x^2+(2a_2+a_1)x+a_1+a_0)e^x-be^{-x}
{y_p}''=(a_2x^2+(4a_2+a_1)x+2a_2+2a_1+a_0)e^x+be^{-x}

Substituting into the ODE, the left hand side reduces significantly to

2a_2e^x+4be^{-x}=2e^x-3e^{-x}

and it follows that

\begin{cases}2a_2=2\\4b=-3\end{cases}\implies a_2=1,b=-\dfrac34

Therefore the particular solution is

y_p=x^2e^x-\dfrac34e^{-x}

and so the general solution is the sum of the characteristic and particular solutions,

y=y_c+y_p
y=C_1e^x+C_2xe^x+x^2e^x-\dfrac34e^{-x}
3 0
3 years ago
Alaina went to Applebee's for dinner with some friends.
SVETLANKA909090 [29]

Answer:

they saved $10.29

Step-by-step explanation:

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3 years ago
How do I find the radius of a cone when given the volume
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Multiply the volume by 3. For example, the volume is 20. ... Multiply the height by π, which is a numeric constant that begins 3.14 and never terminates. ... Divide the tripled volume by the product of the height and π. ... <span>Find the square root of the result from Step 3.</span>
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3 years ago
Read 2 more answers
a student ran out of time on a multiple choice exam and randomly guess the answers for two problems each problem have four answe
katen-ka-za [31]

Answer:

The probability that he answered neither of the problems correctly ​is 0.0625.

Step-by-step explanation:

We are given that a student ran out of time on a multiple-choice exam and randomly guess the answers for two problems each problem have four answer choices ABCD and only one correct answer.

Let X = <u><em>Number of problems correctly ​answered by a student</em></u>.

The above situation can be represented through binomial distribution;

P(X=r)=\binom{n}{r}\times p^{r}\times (1-p)^{n-r};x=0,1,2,3,....    

where, n = number of trials (samples) taken = 2 problems

           r = number of success = neither of the problems are correct

           p = probability of success which in our question is probability that

                 a student answer correctly, i.e; p = \frac{1}{4} = 0.75.

So, X ~ Binom(n = 2, p = 0.75)

Now, the probability that he answered neither of the problems correctly ​is given by = P(X = 0)

             P(X = 0) = \binom{2}{0}\times 0.75^{0}\times (1-0.75)^{2-0}

                            = 1 \times 1\times 0.25^{2}

                            = <u>0.0625</u>

6 0
4 years ago
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