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Montano1993 [528]
2 years ago
10

I need help with this​

Mathematics
2 answers:
galina1969 [7]2 years ago
6 0

Answer:

87

Step-by-step explanation:

75% is essentially the same as 0.75

0.75 times 116 is 87.

stealth61 [152]2 years ago
6 0

Answer:

It is 87

Step-by-step explanation:

75% can also be written as 0.75 so

116×0.75 is 87

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hector buys a used car with an odometer reading of 42,450 miles. after the first month, the mileage sbows an increase of 5%. Aft
Usimov [2.4K]
5% Of 42,450 (.05*42,450=2,122.5)
2,122.5+42,450=44,572.5
4% of 44,572.5 (.04*44,572.5=1,782.9)
1,782.9+44,572.5=46,355.4

The answer is 46,355.4 miles
8 0
4 years ago
Read 2 more answers
A study was conducted to investigate the effectiveness of hypnotism in reducing pain. An SRS of 8 subjects was randomly selected
chubhunter [2.5K]

Answer:

e. No, the p-value is greater than 0.01, so there is insufficient evidence at the 0.01 level to conclude that pain levels are lower after hypnotism.

Step-by-step explanation:

Hello!

The study's objective is to test if hypnotism reduces pain.

A sample of n=8 subjects was taken and the pain level was recorded in each subject before and after being hypnotized.

The variable of interest was determined by calculating the difference of pain level after - before hypnosis. This is a paired sample test and the variable can be determined as:

Xd: Difference between pain level felt after hypnosis and pain level felt before hypnosis of a subject.

The sample average and standard deviation obtained were:

Xd= -3

Sd= 3

And the variable is presumed to be approximately normal.

An approximately normal distribution is enough to conduct a paired sample t-test.

If the claim is that hypnosis reduces pain, then the average pain level after hypnosis should be less than the average pain level before hypnosis, then the average difference is expected to be negative, symbolically: μd < 0

The test will be one-tailed and so will be the p-value.

Remember: The p-value is defined as the probability corresponding to the calculated statistic if possible under the null hypothesis (i.e. the probability of obtaining a value as extreme as the value of the statistic under the null hypothesis).

So first step is to calculate the value of the statistic under the null hypothesis and then you can calculate the p-value.

H₀: μd ≥ 0

H₁: μd < 0

t_{H_0}= \frac{X_d-Mu_{d}}{\frac{S_d}{n} }= \frac{-0-0}{\frac{3}{\sqrt{8} } } = -2.828= -2.83

The DF of the t-test are n-1= 7

Then you can calculate the p-value as:

P(t₇≤-2.83)= 0.0127

The level of the test is α: 0.01

The decision rule is:

If p-value ≤ α, reject the null hypothesis.

If p-value > α, do not reject the null hypothesis.

The p-value > α the decision is to not reject the null hypothesis.

Correct option: e. No, the p-value is greater than 0.01, so there is insufficient evidence at the 0.01 level to conclude that pain levels are lower after hypnotism.

I hope this helps!

5 0
4 years ago
Determine the discount between the point(-4,2) and the line 4y=3×+6​
frozen [14]

Answer:

d = 14/5

Step-by-step explanation:

The point (-4,2) means that;

At x = -4, y = 2

Now general form of a linear equation is;

Ax + By + C = 0

We are given;

4y = 3x + 6​

Rearranging to the form of a linear equation gives;

3x - 4y + 6 = 0

Thus, A = 3, B = -4 and C = 6

Thus, at point (-4,2), distance between them is;

d = (3(-4) - 4(2) + 6)/√(3² + (-4)²)

d = -14/5

We will take the absolute value.

Thus; d = 14/5

6 0
3 years ago
What is the value of 125 ⅔ ?​
horrorfan [7]

Answer:125.666

Step-by-step explanation:

8 0
2 years ago
Is this equation an identity?<br><br> z = -10 − z
Umnica [9.8K]

Answer:

y

Step-by-step explanation:

3 0
3 years ago
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