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katrin [286]
3 years ago
15

Let ​f(x)=x2+10x+37​ .

Mathematics
1 answer:
Gnesinka [82]3 years ago
7 0

Answer:

f(x) = (x+5)^2 +12

The minimum value is 12

Step-by-step explanation:

f(x)=x^2+10x+37

The vertex will be the minimum value since this is an upwards opening parabola

Completing the square by taking the coefficient of x and squaring it adding it and subtracting it

f(x) = x^2+10x  + (10/2) ^2 - (10/2) ^2+37

f(x) = ( x^2 +10x +25) -25+37

    = ( x+5) ^2+12

Th is in vertex form y = ( x-h)^2 +k  where (h,k) is the vertex

The vertex is (-5,12)

The minimum is the y value or 12

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For this case, the first thing to do is to calculate the time you were watching the game.
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3 years ago
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3 years ago
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kicyunya [14]

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Urgent help... looks easy... just can't get it :(0.
r-ruslan [8.4K]
Answer: Choice D

-------------------------------------

Work Shown:

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