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2 years ago

Please answer the question in the picture

Mathematics

2 answers:

olga nikolaevna [1]2 years ago

4 0

answer:

$(3x+5)(x+1)$

explanation:

$3x^2 +8x + 5$

$3x^2 +3x+5x + 5$

$3x(x+1)+5(x+1)$

$(3x+5)(x+1)$

jenyasd209 [6]2 years ago

3 0

$3x² + 8x + 5$

$3x² + 3x + 5x +5$

$3x(x + 1) +5(x + 1)$

$(3x + 5) (x + 1)$

Answer :— $(3x + 5) (x + 1)$

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Which number is irrational A. 2.7 B. -2. 7 C. 2/7 D. √7

pashok25 [27]

Answer:

Step-by-step explanation:

because $\sqrt{7}$ is radical

6 0

2 years ago

Read 2 more answers

Please help me!!!!! How do you get 67.3 and 112.7 from .9228

antoniya [11.8K]

Answer and Step-by-step explanation:

You are correct in that we need to use the Law of Sines: $\frac{c}{sinC} =\frac{b}{sinB}=\frac{a}{sinA}$ .

Here, when we use the Law of Sines, we have: $\frac{28}{sin(63)}=\frac{29}{sinB}$ .

Cross multiply:

(sinB) * 28 = (sin63) * 29

28sinB ≈ 25.839

sinB ≈ 0.9228

Now, in order to solve for B, we need to use inverse sin ( $sin^{-1}$ ):

$sin^{-1}(sinB)=sin^{-1}(0.9228)$

The sines on the left cancel out, and we're left with:

B ≈ 67.3 degrees

Now, one thing to keep in mind when doing Law of Sines is that there is potentially more than one answer possible for the degree measure. The other degree measure can be found by subtracting this one from 180:

180 - 67.3 = 112.7 degrees.

Hope this helps!

7 0

3 years ago

Read 2 more answers

write a function g whose graph represents a translation 2 units to the right followed by a horizontal stretch by a factor or 2 o

Alenkinab [10]

$\bf f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}\\\\
f(x)=&{{ A}} \left|{{ B }}x+{{ C}} \right|+{{ D}}
\\\\
--------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

with that template in mind, let's see,

$\bf f(x)=|x| \implies \begin{array}{lllccll}
f(x)=&1|&1x&+0|&+0\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}$

so, to shift it to the right by 2 units, simply set C = 2.
to stretch it by 2, set A = 1/2.

the smaller A is, the wider it opens, the larger it is, the more it shrinks.

5 0

3 years ago

Grace [21]

Answer:

It is C) 110° I just did it on USA Testprep

8 0

3 years ago

A) y=5x+5<br> B)y=x+5<br> C)y=5x+25<br> D)y=x+125

kirill115 [55]

The answer of the question is C

6 0

2 years ago