Answer:
140
Step-by-step explanation:
140
Assuming the distribution is continuous, you have
![\mathbb E(X)=\displaystyle\int_1^{29}\frac x{29-1}\,\mathrm dx=\dfrac1{28}\int_1^{29}x\,\mathrm dx=15](https://tex.z-dn.net/?f=%5Cmathbb%20E%28X%29%3D%5Cdisplaystyle%5Cint_1%5E%7B29%7D%5Cfrac%20x%7B29-1%7D%5C%2C%5Cmathrm%20dx%3D%5Cdfrac1%7B28%7D%5Cint_1%5E%7B29%7Dx%5C%2C%5Cmathrm%20dx%3D15)
If instead the distribution is discrete, the value will depend on how the interval of number between 1 and 29 are chosen - are they integers? evenly spaced rationals? etc
Answer:
Bottom left.
Step-by-step explanation:
In order for any of them to be the graph of a function you would need that given a value of x, you get no more than one value of y. Zero is fine, you just picked an x out of the domain.
In layman's terms it means that if you grab a ruler, a piece of paper, a pen, and you scan the graph moving the edge parallel to the y axis (ie, vertically) you are allowed to touch the graph only once. Top right is out. Bottom left is ok, bottom right is not: you have infinite points of contact in there.
Top left would be fine, if it wasn't for x = 1. In there you have two values marked with a solid dot. That makes it not the graph of a function.
Answer:
Any linear equation of the slope-intercept form y =7x/4+ b will be parallel to y=7x/4, since the slope of 7/4 will be the same for all such lines
Step-by-step explanation:
Answer:
Yes
Step-by-step explanation:
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