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Otrada [13]
2 years ago
6

In 2010, the population of a city was 114,000. From 2010 to 2015, the population grew by 7.7%. From 2015 to 2020, it fell by 6.6

%. How much did the population grow from 2010 to 2015, to the nearest 100 people?
Mathematics
1 answer:
vovikov84 [41]2 years ago
6 0

Answer:

From 2010 to 2015 the population grew by 8778 (rounded answer 8800)

Step-by-step explanation:

*

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What are two`fractions whose product is -3/5
natali 33 [55]
7/5 - 10/5 = -3/5

I hope this helps. 
3 0
3 years ago
2|3x - 2|= 14 how would you solve this absolute value equation?
Feliz [49]

Answer: 2. |3x-2|= 14

|3x-2|=2.7/2

|3x-2|=7

x∈ {3,-5/3

Step-by-step explanation: \frac{5}{3}

6 0
2 years ago
Read 2 more answers
S
lora16 [44]

Answer:

  B.  9

Step-by-step explanation:

We assume that ...

  SU = ST +TU

  133 = (9x-5) +(5x+12)

  126 = 14x . . . . . subtract 7, collect terms

  9 = x . . . . . . . . . divide by 14

7 0
3 years ago
Identify the x-intercept and the y-intercept of the graph of 6x + 15y = −30.
Hunter-Best [27]

Answer:

D. x-intercept is -5 and the y-intercept is -2

5 0
2 years ago
Find the payment necessary to amortize a 6.3% loan of 7500 compounded semiannually, with 6 semiannual payments. Find the payment
Lorico [155]

Answer:

Semiannual payment = $ 1391.37

Total payment = $ 8348.22

Interest paid =  $ 848.22

Step-by-step explanation:

Since, the semiannual payment formula of a loan,

P=\frac{PV(\frac{r}{2})}{1-(1+\frac{r}{2})^{-n}}

Where,

PV = present value of the loan,

n = number of semiannual payments,

r = annual rate,

Here, PV = 7500, r = 6.3% =0.063, n = 6,

By substituting the value,

The semiannual payment would be,

P=\frac{7500(\frac{0.063}{2})}{1-(1+\frac{0.063}{2})^{-6}}

\approx \$ 1391.37

Also, total payment = semiannual payment × total semiannual periods

= 1391.37 × 6

= $ 8348.22,

Also, the interest paid = total payment - present value

= 8348.22 - 7500

= $ 848.22

6 0
3 years ago
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