Ask question

Ask question

All categories

2 years ago

6

In 2010, the population of a city was 114,000. From 2010 to 2015, the population grew by 7.7%. From 2015 to 2020, it fell by 6.6

%. How much did the population grow from 2010 to 2015, to the nearest 100 people?

1 answer:

vovikov84 [41]2 years ago

6 0

Answer:

From 2010 to 2015 the population grew by 8778 (rounded answer 8800)

Step-by-step explanation:

*

You might be interested in

Three fourths of the flowers in a floral arrangement is red roses. Write the part of the flowers that are red roses as a decimal

makvit [3.9K]

Answer:

decimal: 0.75 percent: 75%

8 0

2 years ago

For f(x) = 3x^2 + 2x - 1, identify the rule for g(x) = f(x + 1) - 6 and it's graph.

PilotLPTM [1.2K]

2x2 + x −#6 _____________

x2 − 1

∙ x

__

2 + 2x + 1

x 2 − 4

Rewrite as multiplication.

(2x − 3)(x + 2) __

(x + 1)(x − 1) ∙ (x + 1)(x + 1) __ (x + 2)(x − 2) Factor the numerator and denominator.

(2x − 3)(x + 2)(x + 1)(x + 1) ___ (x + 1)(x − 1)(x + 2)(x − 2) Multiply numerators and denominators.

(2x − 3)(x + 2)(x + 1)(x + 1) ___ (x + 1)(x − 1)(x + 2)(x − 2) Cancel common factors to simplify.

(2x − 3)(x + 1) __ (x − 1)(x − 2)

4 0

3 years ago

PLEASEE HELPP ANYONE

almond37 [142]

Answer: B. Exponential. There is a constant rate of decay or decrease.

The y-values decrease by 1/4 of the number that comes before every time.

5 0

3 years ago

Read 2 more answers

Can someone help me find the equivalent expressions to the picture below? I’m having trouble

miss Akunina [59]

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is $\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$ .

Now we will solve this expression with the help of law of exponents.

$\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}$

$=2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}$

$=2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}$

$=2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}$

$=2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }$ [Option 2]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$ [Option 1]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$

$=(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }$

$=\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} }$ [Option 3]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }$

$=\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}}$ [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

6 0

2 years ago

Write the equation of the line parallel to 5x + y = -2 that goes through the point (2, -3).

gladu [14]

Answer:

y = -5x + 7

Step-by-step explanation:

Slope-Intercept Form: y = mx + b

Step 1: Define

5x + y = -2

Random point (2, -3)

Step 2: Rewrite

y = -5x - 2

m = -5

Step 3: Write parallel line

y = -5x + b

-3 = -5(2) + b

-3 = -10 + b

7 = b

y = -5x + 7

8 0

2 years ago