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Mashutka [201]
2 years ago
5

Graph the equation y=-x^2-2x+3 on the accompanying set of axes. You must plot 5 points including the roots and the vertex.

Mathematics
1 answer:
Advocard [28]2 years ago
3 0

Answer:

See below (along with attached graph)

5th point can be of personal choice

Step-by-step explanation:

<u>X-intercepts/Roots</u>

y=-x^2-2x+3\\\\0=-x^2-2x+3\\\\0=-(x^2+2x-3)\\\\0=-(x+3)(x-1)\\\\x=-3,\: x=1\\\\(-3,0)\:and\:(1,0)

<u>Y-intercept</u>

y=-x^2-2x+3\\\\y=-(0)^2-2(0)+3\\\\y=3\\\\(0,3)

<u>Vertex</u>

x=-\frac{b}{2a}\\ \\x=-\frac{(-2)}{2(-1)}\\ \\x=\frac{2}{-2}\\ \\x=-1\\\\y=-x^2-2x+3\\\\y=-(-1)^2-2(-1)+3\\\\y=-1+2+3\\\\y=4\\\\(-1,4)

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