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Elena L [17]
2 years ago
11

the wires are separated by 0.20 m. at what point between the two wires are the contributions from the two wires the same?

Mathematics
1 answer:
Yuri [45]2 years ago
8 0

Answer:

B

Step-by-step explanation:

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Solve using substitution<br><br> y=1/2x<br> x+4y=18
Aleks [24]

Answer:

The solution set is (6,3)

Step-by-step explanation:

Begin by multiplying equation 1 by 2. You'll see why in a moment

2y = 2*(1/2) x

2y = x

Substitute this value into equation 2.

2y + 4y = 18                  Combine like terms on the left

6y = 18                          Divide both sides by 6

6y/6 = 18/6                    Do the division

y = 3

To solve for x just use the top equation

y = 1/2x

3 = 1/2x                          Multiply by 2

3*2 = x

x = 6


7 0
3 years ago
Working alone Ryan can dig a 10ft by 10ft hole in five hours castel can dig the same same hole in six how long would it take the
Sergeeva-Olga [200]

Answer:

The time taken by both when they work together is 2 hours 42 minutes .

Step-by-step explanation:

Given as :

The time taken by Ryan to dig 10 ft by 10 ft hole = x = 5 hours

The time taken bu Castel to dig 10 ft by 10 ft hole = y = 6 hours

Let The time taken by both when they work together = z hours

<u>According to question</u>

The time taken by both when they work together = time taken by Ryan to dig 10 ft by 10 ft hole + time taken bu Castel to dig 10 ft by 10 ft hole

i.e \dfrac{1}{z} = \dfrac{1}{x} + \dfrac{1}{y}

Or,  \dfrac{1}{z} = \dfrac{1}{5}  +  \dfrac{1}{6}

<u>Taking LCM</u>

Or,  \dfrac{1}{z} = \dfrac{6 + 5}{30}

Or,  \dfrac{1}{z} = \dfrac{11}{30}

Or, z = \dfrac{30}{11}   hours

∴  z = 2 hours 42 minutes

So, The time taken by both when they work together = z = 2 hours 42 min

Hence, The time taken by both when they work together is 2 hours 42 minutes . Answer

3 0
3 years ago
Determine the current through each of the LEDs in the circuits below. Which LED will be
Anika [276]

a. I = 6. 1 × 10^-4 A

b. I = 2. 6 × 10^-3 A

c. I = 0. 04 A

The LED which would glow brightest is LED C with the greatest current and voltage

The LED which would be the most dim is LED B with low voltage and consequently low current.

<h3>How to determine the current</h3>

The formula for finding current

I = V/R

Where v = voltage

R = resistance

A. V = 12V

R = 4. 7 + 15 = 19. 7 kΩ = 19700 Ω in series

I = \frac{12}{19700}

I = 6. 1 × 10^-4 A

B. V = 9V

R = 4. 7 + 1 = 4. 7 kΩ = 4700Ω in series

I = \frac{12}{4700}

I = 2. 6 × 10^-3 A

C.  V=  12V

1/R = \frac{1}{750} + \frac{1}{1200} + \frac{1}{950 } = 3. 22 × 10^-3

R = \frac{1}{3. 22 * 10 ^-3} = 310. 56 Ω

I = \frac{12}{310. 56}

I = 0. 04 A

It is important to note that the brightness of a bulb depends on both current and voltage depending on whether the bulb it is in parallel or series.

The LED which would glow brightest is LED C with the greatest current and voltage

The LED which would be the most dim is LED B with low voltage and consequently low current.

Learn more about Ohms law here:

brainly.com/question/14296509

#SPJ1

8 0
2 years ago
It takes you 39 seconds to walk from the first​ (ground) floor of a building to the third floor. how long will it take you to wa
nalin [4]
It will take you double the time, or 78 seconds.
6 0
3 years ago
What would this equal up to
Dovator [93]

Answer:

Step-by-step explanation:

\text{Count the zeros, there are seven so }10^7

7 0
3 years ago
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