All categories

2 years ago

What would happen to the variance of a data set if we multiplied every observation by S?

1 answer:

4 0

The variance of a constant is zero. Rule 2. Adding a constant value, c, to a random variable does not change the variance, because the expectation (mean) increases by the same amount. ... Multiplying a random variable by a constant increases the variance by the square of the constant.

You might be interested in

A large oak tree has 2 x 10⁵ leaves during

Rom4ik [11]

I’m pretty sure it’s this 200,000

4 0

3 years ago

I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS PLEASE AND PLEASE EXPLAIN WHY THAT IS THE ANSWER

melamori03 [73]

Answer: 5x 5y

Step-by-step explanation: because of the length

4 0

2 years ago

Please hellppppp asap

Pani-rosa [81]

Answer:

1. comeptition. base word: compete

2. protection. base word: protect

3.rotation. base word: rotate

4.application. base word: apply

5. division. base word: divide

6. organisation. base word: organise

7. production. base word: produce

8. solution: base word: solve

9. opposition. base word: oppose

10. operation. base word: operate

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Logarithmic and exponential functions are used in which of the following areas

3241004551 [841]

Answer:

exist in areas like physical science, electronics, business, and social sciences. hope this helps

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Suppose log subscript a x equals 3, log subscript a y equals 7, and log subscript a z equals short dash 2. Find the value of the

enyata [817]

Answer:

Step-by-step explanation:

Given the following logarithmic expressions $log_ax = 3, log_ay = 7, log_az = -2$ , we are to find the value of $log_a(\frac{x^3y}{z^4} )$

$from\ log_ax = 3, x = a^3\\\\from\ log_ay = 7,y = a^7\\\\from\ log_az = -2, z = a^{-2}$ Substituting x = a³, y = a⁷ and z = a⁻² into the log function $log_a(\frac{x^3y}{z^4} )$ we will have;

$= log_a(\frac{x^3y}{z^4} )\\\\= log_a(\dfrac{(a^3)^3*a^7}{(a^{-2})^4} )\\\\= log_a(\dfrac{a^9*a^7}{a^{-8}} )\\\\= log_a\dfrac{a^{16}}{a^{-8}} \\\\= log_aa^{16+8}\\\\= log_aa^{24}\\\\= 24log_aa\\\\= 24* 1\\\\= 24$

Hence, the value of the logarithm expression is 24

6 0

3 years ago