Answer:
a) P ( 3 ≤X≤ 5 ) = 0.02619
b) E(X) = 1
Step-by-step explanation:
Given:
- The CDF of a random variable X = { 0 , 1 , 2 , 3 , .... } is given as:
Find:
a.Calculate the probability that 3 ≤X≤ 5
b) Find the expected value of X, E(X), using the fact that. (Hint: You will have to evaluate an infinite sum, but that will be easy to do if you notice that
Solution:
- The CDF gives the probability of (X < x) for any value of x. So to compute the P ( 3 ≤X≤ 5 ) we will set the limits.
- The Expected Value can be determined by sum to infinity of CDF:
E(X) = Σ ( 1 - F(X) )
E(X) = Limit n->∞ [1 - 1 / ( n + 2 ) ]
E(X) = 1
-18
1) Distribute the -6 to the parentheses
-4 - (6*7) - (-6*3)
2) Simplify
-4 - 42 + 18
-18
9514 1404 393
Answer:
x = 22.5°
Step-by-step explanation:
The interior angle at E is (180 -4x), the supplement of the exterior angle there, 4x. The sum of angles 2x and (180-4x) will be equal to 6x, because alternate interior angles at transversal BE are congruent:
2x +(180 -4x) = 6x
180 = 8x . . . . . . . add 2x and simplify
22.5 = x . . . . . . . divide by 8
The value of x is 22.5°.
Description:
This will be no solution because when we add 10 to both sides of the equation then simplify it. After that we will subtract 6 from both sides. It will give us no solution. For more info please see the attachment.
Answer: No solution
Hope this helps.
Sin2x=2sinxcosx
sin2x/5=2sinx/5cosx/5
hence the nuber 2 multiply by cosx/5sinx/5 can be divided on the other side
hence its true
