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dmitriy555 [2]
3 years ago
12

HELP ASAP:( Roberto lives thirty-eight miles from his college. During school, he rides his bike at 5 mph to the bus station. He

then takes the bus to school which travels at 34 mph. If he spends 12 minutes less on his bike than on the bus, what is the distance from his house to the bus station? Hint: 12 minutes = 0.20 hours
Mathematics
2 answers:
Anika [276]3 years ago
6 0

Answer:

Step-by-step explanation:

ding the math I am pretty sure it is 7miles because mph 12 minutes= 0.20 hours meaning how many miles in 12 minutes moved

KATRIN_1 [288]3 years ago
5 0

Answer:

Step-by-step explanation:

4 miles I believe

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C is the correct answer 3.785*2.5=9.4625 then multiply by 1000 and you get 9,462.5

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Factor as the product of two binomials. x^2 + 3x +2
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If you had 1052 toothpicks and were asked to group them in powers of 6, how many groups of each power of 6 would you have? Put t
sukhopar [10]

1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

The number 1052, written as a base 6 number is 4512

Given: 1052 toothpicks

To do: The objective is to group the toothpicks in powers of 6 and to write the number 1052 as a base 6 number

First we note that, 6^{0}=1,6^{1}=6,6^{2}=36,6^{3}=216,6^{4}=1296

This implies that 6^{4} exceeds 1052 and thus the highest power of 6 that the toothpicks can be grouped into is 3.

Now, 6^{3}=216 and 216\times 5=1080, 216\times 4=864. This implies that 216\times 5 exceeds 1052 and thus there can be at most 4 groups of 6^{3}.

Then,

1052-4\times6^{3}

1052-4\times216

1052-864

188

So, after grouping the toothpicks into 4 groups of third power of 6, there are 188 toothpicks remaining.

Now, 6^{2}=36 and 36\times 5=180, 36\times 6=216. This implies that 36\times 6 exceeds 188 and thus there can be at most 5 groups of 6^{2}.

Then,

188-5\times6^{2}

188-5\times36

188-180

8

So, after grouping the remaining toothpicks into 5 groups of second power of 6, there are 8 toothpicks remaining.

Now, 6^{1}=6 and 6\times 1=6, 6\times 2=12. This implies that 6\times 2 exceeds 8 and thus there can be at most 1 group of 6^{1}.

Then,

8-1\times6^{1}

8-1\times6

8-6

2

So, after grouping the remaining toothpicks into 1 group of first power of 6, there are 2 toothpicks remaining.

Now, 6^{0}=1 and 1\times 2=2. This implies that the remaining toothpicks can be exactly grouped into 2 groups of zeroth power of 6.

This concludes the grouping.

Thus, it was obtained that 1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

Then,

1052=4\times6^{3}+5\times6^{2}+1\times6^{1}+2\times6^{0}

So, the number 1052, written as a base 6 number is 4512.

Learn more about change of base of numbers here:

brainly.com/question/14291917

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Find the slope of the line that passes through (4, 6) and (1, 10).
Jlenok [28]

Answer:

given us,

(x1y1) = (4,6)

(x2y2)= (1,10)

here

slope= (y2-y1)/ (x2-x1)

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= 4/ (-3)

Step-by-step explanation:

4/ (-3)

5 0
3 years ago
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