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ruslelena [56]
2 years ago
12

A quadrilateral is shown. One pair of opposite sides have lengths of 10 inches and (x + 2) inches. The other pair of opposite si

des have lengths (x + 5) inches and (2 x minus 3) inches. Based on the measures shown, could the figure be a parallelogram? 1.Yes, one pair of opposite sides could measure 10 in., and the other pair could measure 13 in. 2.Yes, one pair of opposite sides could measure 10 in., and the other pair could measure 8 in. 3.No, there are three different values for x when each expression is set equal to 10. 4.No, the value of x that makes one pair of sides congruent does not make the other pair of sides congruent.
Mathematics
2 answers:
SOVA2 [1]2 years ago
8 0

Answer:

  • 1. Yes, one pair of opposite sides could measure 10 in., and the other pair could measure 13 in.

Step-by-step explanation:

<u>The opposite pairs are:</u>

1)

  • 10 in with x + 2 in
  • It makes:
  • x =+2 = 10 ⇒ x = 8 and both sides 10 in

2)

x + 5 with 2x - 3

<u>It makes:</u>

  • 2x - 3 = x + 5
  • 2x - x = 5 + 3
  • x = 8

<u>The sides are:</u>

  • 8 + 5 = 13 and
  • 2*8 - 5 = 13 in

Correct answer choice is 1)

ddd [48]2 years ago
3 0

Sides given by

  • 10
  • x+2
  • x+5
  • 2x+3

Opposite sides must be equal

Let's check once

\\ \tt\hookrightarrow x+5=2x+3\implies x=2

Find sides now

  • 10in
  • 2+2=4in
  • 2+5=7in
  • 2(2)+3=4+3=7in

One pair of opposite sides are equal but others not .

  • It's a trapezium.

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Svetllana [295]
Hello!

We can write this as the system of equations below. We have boxes A, B, and C.

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First of all we can plug our B and C values into the first equation and solve for A.

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Now we can plug our a value into the other equations.

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Therefore, there are 2 rocks in one box, three in another, and 4 in the last.

I hope this helps!
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