Base area* height
base area:
parallelogram: width*length
triangles: (height * base) /2
Answer:
Step-by-step explanation:
Given that the owner of a motel has 2900 m of fencing and wants to enclose a rectangular plot of land that borders a straight highway.
Fencing is used for 2times length and 1 width if highway side is taken as width
So we have 2l+w = 2900
Or w = 2900-2l
Area of the rectangular region = lw
Use derivative test to find the maximum
So maximum when I derivative =0
i.e when 
Largest area = A(725)
= 
1051250 sqm is area maximum
Ok, here we go:
5 cars total.
1. Rachel - first car in line, yellow, SUV
2. blue car (Rachel is in front of the blue car), convertible, Anton
3. minivan - third car in line, Diego
4. white car, sedan, Ingrid
5. green car, immediately behind white car, Yuna, pickup
We know that Rachel is first, a blue car is second and the minivan is third. We know that 3, 4 cannot be a convertible since one is a minivan and the other is a sedan. We also know that a yellow car is in front of the convertible.
Based off of that we know that car 5 cannot be a convertible since 4 is white and not yellow. So 1 or 2 is the convertible and SUV. But we know that Rachel is in front of a blue car and the yellow car is in front of a convertible so that makes car #2 the blue convertible and car #1 the yellow SUV.
Fill in what you do know and start to eliminate the outliers. Hope that helps.
Round to the biggest place value, 2,356 in the thousands place so the thousandths place is the greatest value there so 2,356 rounded to the nearest thousandths is 2,000
Answer:
length : 15 ft
width : 3 ft
Step-by-step explanation:
perimeter = 2×l(ength) + 2×w(idth) = 36
l = 3w + 6
=> 2×(3w+6) + 2w = 36
6w + 12 + 2w = 36
8w = 24
w = 3
=> l = 3w + 6 = 3×3 + 6 = 9+6=15
