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Furkat [3]
3 years ago
12

I need help please help!

Mathematics
1 answer:
Blababa [14]3 years ago
4 0

Answer:

50.5 m^3

Step-by-step explanation:

Volume of pyramid = 1/3 × base area × height.

  • Height: 11
  • Base Dimensions: 4.3 and 3.2

Area of Base:

  • 4.3 * 3.2
  • 13.76  

Next, we multiply 13.76 by 11.

  • 13.76 × 11
  • 151.36

Lastly, divide by 3 and round to nearest tenth.

  • 151.36 ÷ 3  
  • 50.453333..
  • ≈ 50.5

Therefore, the answer is 50.5 m^3

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Convert 3.521 g to ___ mg
inna [77]

To convert any unit to it's "milli-" form always multiply the given value by 1000. The new value will be the value of in the "milli-" form.

The question asked to us is to convert 3.521 g to mg (or milligram). Thus, all that we need to do is to multiply 3.521 with 1000 and we will get the corresponding value in milligrams. Thus, in mg, 3.521 g is:

3.521\times 1000=3521 mg

6 0
3 years ago
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In a bag,There are red and blue cubes in the ratio 4:7.I add 10 more red cubes to the bag.Now here are red and blue cubes in the
Hoochie [10]

Given:

The ratio of red and blue cubes is 4:7.

After adding 10 more red cubes the ratio of red and blue cubes is 6:7.

To find:

The number of blue cubes.

Solution:

The ratio of red and blue cubes is 4:7.

Let the number of red and blue cubes be 4x and 7x respectively.

After adding 10 more red cubes.

Number of red cubes = 4x+10

Then, the ratio of red and blue cubes is 6:7.

\dfrac{4x+10}{7x}=\dfrac{6}{7}

7(4x+10)=6(7x)

28x+70=42x

70=42x-28x

70=14x

Divide both sides by 14.

5=x

Now,

Number of blue cubes in the bag is

7(5)=35

Therefore, the number of blue cubes is 35.

5 0
3 years ago
Find the exact value of tan(165°) using a difference of two angles
Katyanochek1 [597]

Answer:  -2+\sqrt{3}

=========================================================

Work Shown:

Apply the following trig identity

\tan(A - B) = \frac{\tan(A)-\tan(B)}{1+\tan(A)*\tan(B)}\\\\\tan(225 - 60) = \frac{\tan(225)-\tan(60)}{1+\tan(225)*\tan(60)}\\\\\tan(165) = \frac{1-\sqrt{3}}{1+1*\sqrt{3}}\\\\\tan(165) = \frac{1-\sqrt{3}}{1+\sqrt{3}}\\\\

Now let's rationalize the denominator

\tan(165) = \frac{1-\sqrt{3}}{1+\sqrt{3}}\\\\\tan(165) = \frac{(1-\sqrt{3})(1-\sqrt{3})}{(1+\sqrt{3})(1-\sqrt{3})}\\\\\tan(165) = \frac{(1-\sqrt{3})^2}{(1)^2-(\sqrt{3})^2}\\\\\tan(165) = \frac{(1)^2-2*1*\sqrt{3}+(\sqrt{3})^2}{(1)^2-(\sqrt{3})^2}\\\\\tan(165) = \frac{1-2\sqrt{3}+3}{1-3}\\\\\tan(165) = \frac{4-2\sqrt{3}}{-2}\\\\\tan(165) = -2+\sqrt{3}\\\\

----------------------

As confirmation, you can use the idea that if x = y, then x-y = 0. We'll have x = tan(165) and y = -2+sqrt(3). When computing x-y, your calculator should get fairly close to 0, if not get 0 itself.

Or you can note how

\tan(165) \approx -0.267949\\\\-2+\sqrt{3} \approx -0.267949

which helps us see that they are the same thing.

Further confirmation comes from WolframAlpha (see attached image). They decided to write the answer as \sqrt{3}-2 but it's the same as above.

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3 years ago
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marin [14]
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A is correct.

B. y = ²/₃ - 5
B is also correct.

C. 6y = 4x - 30
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C is also correct.

D. y + 3 = ²/₃(x - 3)
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D is also correct.

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