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Furkat [3]
2 years ago
12

I need help please help!

Mathematics
1 answer:
Blababa [14]2 years ago
4 0

Answer:

50.5 m^3

Step-by-step explanation:

Volume of pyramid = 1/3 × base area × height.

  • Height: 11
  • Base Dimensions: 4.3 and 3.2

Area of Base:

  • 4.3 * 3.2
  • 13.76  

Next, we multiply 13.76 by 11.

  • 13.76 × 11
  • 151.36

Lastly, divide by 3 and round to nearest tenth.

  • 151.36 ÷ 3  
  • 50.453333..
  • ≈ 50.5

Therefore, the answer is 50.5 m^3

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Question is down below
Bingel [31]

This is a great question!

To determine the probability with which two sweets are not the same, you would have to subtract the probability with which two sweets are the same from 1. That would only be possible if she chose 2 liquorice sweets, 5 mint sweets and 3 humburgs -

Probability( 2 Liquorice) = 12 / 20 * 11 / 19

As you can see, the first time you were to choose a Liquorice, there would be 12 out of the 20 sweets present. After taking that out however, there would be respectively 11 Liquorice out of 19 remaining. Apply the same concept to each of the other sweets -

Probability(2 Mint ) = 5 / 20 * 4 / 19,\\Probability( 2 Humbugs ) =  3/20 * 2/19

____

Calculate the probability of drawing 2 of each, add them together and subtract from one to determine the probability that two sweets will not be the same type of sweet!

1-\left(\frac{132}{380}+\frac{20}{380}+\frac{6}{380}\right) =\\\frac{111}{190}

<u><em>Thus, the probability should be 111 / 190</em></u>

5 0
3 years ago
A man can drive a motorboat 70 miles down the Colorado River in the same amount of time that he can drive 40 miles upstream. Fin
pochemuha

The speed of the current is 40.34 mph approximately.

<u>SOLUTION: </u>

Given, a man can drive a motorboat 70 miles down the Colorado River in the same amount of time that he can drive 40 miles upstream.  

We have to find the speed of the current if the speed of the boat is 11 mph in still water. Now, let the speed of river be a mph.  Then, speed of boat in upstream will be a-11 mph and speed in downstream will be a+11 mph.

And, we know that, \text{ distance } =\text{ speed }\times \text{ time }

\begin{array}{l}{\text { So, for upstream } \rightarrow 40=(a-11) \times \text { time taken } \rightarrow \text { time taken }=\frac{40}{a-11}} \\\\ {\text { And for downstream } \rightarrow 70=(a+11) \times \text { time taken } \rightarrow \text { time taken }=\frac{70}{a+11}}\end{array}

We are given that, time taken for both are same. So \frac{40}{a-11}=\frac{70}{a+11}

\begin{array}{l}{\rightarrow 40(a+11)=70(a-11)} \\\\ {\rightarrow 40 a+440=70 a-770} \\\\ {\rightarrow 70 a-40 a=770+440} \\\\ {\rightarrow 30 a=1210} \\\\ {\rightarrow a=40.33}\end{array}

8 0
3 years ago
I need help if anyone can help me with a few problems please help me
jok3333 [9.3K]
I think it’s the number 3 I’m not sure I’m learning this stuff rn I’m getting the hang of it just it’s hard and not hard at the same time
5 0
3 years ago
A line goes through the points (5, -1) and (7, -5). What is a possible equation to a new line that is perpendicular?
Leya [2.2K]

<em>Ok, so you are given an equation in standard form, 5x+4y=2, and a point, (7, 5). You are being asked to write the equation for a line that is parallel to the equation in standard from, and that includes the point (7, 5).  </em>

<em> </em>

<em> </em>

<em> </em>

<em>First, let's start by finding the slope of your new line. We know that it needs to have the same slope as 5x+4y=2, because parallel lines have the same slopes. To do that, we need to put the equation into slope-intercept form (y=mx+b), which means we need to isolate the "y."  </em>

<em> </em>

<em> </em>

<em> </em>

<em>  5x+4y=2 </em>

<em> </em>

<em>-5x     -5x  (subtract 5x from both sides to move it to the right side of your equation) </em>

<em> </em>

<em>4y = 2 - 5x </em>

<em> </em>

<em>/4  /4  /4 (divide all the terms by 4 to get "y" by itself) </em>

<em> </em>

<em>y = (1/2) - (5/4)x  ... I suggest leaving your slope as a fraction. </em>

<em> </em>

<em> </em>

<em> </em>

<em>Now, we know that our slope, m , is going to be -(5/4).  </em>

<em> </em>

<em> </em>

<em> </em>

<em>Next, we are going to use our slope, -(5/4), and point, (7, 5), to find the b-value (y-intercept) of your new line. Let's plug in what we know: </em>

<em> </em>

<em> </em>

<em> </em>

<em>y = 5 </em>

<em> </em>

<em>m = -(5/4) </em>

<em> </em>

<em>x = 7 </em>

<em> </em>

<em> </em>

<em> </em>

<em>y=mx+b </em>

<em> </em>

<em>5=(-5/4)(7) + b  -> I plugged in what we knew for y, m, and x.  </em>

<em> </em>

<em>5 = -(35/4) + b  -> I multiplied the numbers in the numerator (5 x 7) to get 35/4 </em>

<em> </em>

<em>20/4 = -(35/4) + b -> I converted 5 into a faction with a denominator of 4 by multiplying by (4/4) </em>

<em> </em>

<em>+(35/4) +(35/4)  -> I add (35/4) to both sides to isolate b </em>

<em> </em>

<em>55/4 = b ... or b = 13.74 </em>

<em> </em>

<em> </em>

<em> </em>

<em>Answer:  </em>

<em> </em>

<em>m = -(5/4) </em>

<em> </em>

<em>b = 13.75</em>

7 0
3 years ago
Use quadratic regression to find
Rashid [163]

The quadratic equation is given by:

y = 3x² + 10x - 8

The standard equation of a parabola is given by:

y = ax² + bx + c

Where a, b, c are constants

At point (4, 80):

80 = a(4)² + b(4) + c

16a + 4b + c = 80     (1)

At point (-3, -11):

-11 = a(-3)² + b(-3) + c

9a - 3b + c = -11     (2)

At point (-1, -15):

-15 = a(-1)² + b(-1) + c

a - b + c = -15     (3)

Solving equations 1, 2 and 3 simultaneously gives:

a = 3, b = 10, c = -8

Therefore the quadratic equation becomes:

y = 3x² + 10x - 8

Find out more on quadratic equation at: brainly.com/question/1214333

8 0
2 years ago
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