Question

A regular octagon has a radius of 6 ft and a side length of 4. 6 ft. A regular octagon has a radius of 6 feet and side lengths of 4. 6 feet. What is the approximate area of the octagon? 71 ft2 101 ft2 110 ft2 202 ft2.

Answer 1

The regular octagon has eight equal sides. Then the area of the regular octagon of side length be 4.6 is 102 ft².

What is a regular octagon?

It is a polygon that has eight equal sides. In a regular octagon, the opposite sides are parallel. And its diagonals are also equal and intersect at mid-point.

Given

A regular octagon has a radius of 6 ft and a side length of 4.6 ft.

We know the formula for the regular octagon.

Area of the regular octagon = 2(1 + $\sqrt{2}$) a²

Where a be the side of a regular octagon.

Then the area of the regular octagon will be.

$\rm Area = 2 (1+\sqrt{2} ) a^2\\\\Area = 2*(1 + 1.414) *4.6^2\\\\Area = 2 * (2.414)* 21.16\\\\Area = 102.16$

Thus, the area of the regular octagon of side length be 4.6 is 102 ft².

More about the regular octagon link is given below.

brainly.com/question/858868