Given:
The first two terms in an arithmetic progression are -2 and 5.
The last term in the progression is the only number in the progression that is greater than 200.
To find:
The sum of all the terms in the progression.
Solution:
We have,
First term : 
Common difference : 


nth term of an A.P. is

where, a is first term and d is common difference.

According to the equation,
.



Divide both sides by 7.

Add 1 on both sides.

So, least possible integer value is 30. It means, A.P. has 30 term.
Sum of n terms of an A.P. is
![S_n=\dfrac{n}{2}[2a+(n-1)d]](https://tex.z-dn.net/?f=S_n%3D%5Cdfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D)
Substituting n=30, a=-2 and d=7, we get
![S_{30}=\dfrac{30}{2}[2(-2)+(30-1)7]](https://tex.z-dn.net/?f=S_%7B30%7D%3D%5Cdfrac%7B30%7D%7B2%7D%5B2%28-2%29%2B%2830-1%297%5D)
![S_{30}=15[-4+(29)7]](https://tex.z-dn.net/?f=S_%7B30%7D%3D15%5B-4%2B%2829%297%5D)
![S_{30}=15[-4+203]](https://tex.z-dn.net/?f=S_%7B30%7D%3D15%5B-4%2B203%5D)


Therefore, the sum of all the terms in the progression is 2985.
Hello from MrBillDoesMath!
Answer:
The first marker is labeled 208708; the second (consecutive) one 208709
Discussion:
Call the first mile marker "m". Then
m + (m+1) = 417417 => combine like terms
2m + 1 = 417417 => subtract 1 from both sides
2m = 417416 => divide both sides by 2
m = 417416/2 = 208708
Note: m and (m+1) are consecutive as they immediately follow each other in the set of integers.
Thank you,
MrB
7 + 18 = 25
25 ÷ 7 = 3.5714285714285714285
so 3.5714285714285714285 is the answer
Answer:
30
Step-by-step explanation:
f(-5) = -7(-5) - 5
= 35 - 5 = 30
12!!!! Hope this helped and good encouragement