Answer:
The solution is ![\frac{1}{10} * tan^{-1}[\frac{e^{2x}}{5} ] + C](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B10%7D%20%2A%20tan%5E%7B-1%7D%5B%5Cfrac%7Be%5E%7B2x%7D%7D%7B5%7D%20%5D%20%2B%20%20C)
Step-by-step explanation:
From the question
The function given is 
The indefinite integral is mathematically represented as

Now let 
=> 
=> 
So

![= \frac{1}{2} \frac{tan^{-1} [\frac{u}{5} ]}{5} + C](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B1%7D%7B2%7D%20%5Cfrac%7Btan%5E%7B-1%7D%20%5B%5Cfrac%7Bu%7D%7B5%7D%20%5D%7D%7B5%7D%20%20%2B%20%20C)
Now substituting for u
![\frac{1}{10} * tan^{-1}[\frac{e^{2x}}{5} ] + C](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B10%7D%20%2A%20tan%5E%7B-1%7D%5B%5Cfrac%7Be%5E%7B2x%7D%7D%7B5%7D%20%5D%20%2B%20%20C)
That's <u>always</u> true if <em>either</em> the exponent <em>or </em>the base is less than ' 1 '.
(But not always of they both are.)
Answer:
The exponential Function is
.
Farmer will have 200 sheep after <u>15 years</u>.
Step-by-step explanation:
Given:
Number of sheep bought = 20
Annual Rate of increase in sheep = 60%
We need to find that after how many years the farmer will have 200 sheep.
Let the number of years be 'h'
First we will find the Number of sheep increase in 1 year.
Number of sheep increase in 1 year is equal to Annual Rate of increase in sheep multiplied by Number of sheep bought and then divide by 100.
framing in equation form we get;
Number of sheep increase in 1 year = 
Now we know that the number of years farmer will have 200 sheep can be calculated by Number of sheep bought plus Number of sheep increase in 1 year multiplied by number of years is equal to 200.
Framing in equation form we get;

The exponential Function is
.
Subtracting both side by 20 using subtraction property we get;

Now Dividing both side by 12 using Division property we get;

Hence Farmer will have 200 sheep after <u>15 years</u>.
Answer:
$26.31
Step-by-step explanation:
Since 3 is half of 6, 3 pairs of shoes would cost half the price.
So...
52.62/2=$26.31