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Nataly_w [17]
3 years ago
5

What 228,643 to the nearest hundred

Mathematics
1 answer:
Annette [7]3 years ago
3 0
228,643 to the nearest hundered is 228,600.
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Find the indefinite integral. (Use C for the constant of integration.) <br> e2x 25 e4x dx.
Sladkaya [172]

Answer:

The solution is  \frac{1}{10} * tan^{-1}[\frac{e^{2x}}{5} ] +  C

Step-by-step explanation:

From the question

    The function given is  f(x) =  \frac{e^{2x}}{ 25 + e^{4x}} dx

The  indefinite integral is  mathematically represented as

          \int\limits  {\frac{e^{2x}}{ 25 + e^{4x}}} \, dx

Now  let  e^{2x} =  u

=>   \frac{du}{dx} 2e^{2x}

=>   2 e^{2x}dx =  du

So

\int\limits  {\frac{e^{2x}}{ 25 + e^{4x}}} \, dx =  \int\limits  {\frac{1}{ 2(25 + u^2)} } \, du

= \frac{1}{2} \int\limits  {\frac{1}{ 25 + u^2)} } \, du

=  \frac{1}{2} \int\limits  {\frac{1}{ 5^2 + u^2)} } \, du

= \frac{1}{2} \frac{tan^{-1} [\frac{u}{5} ]}{5}  +  C

Now substituting for  u

\frac{1}{10} * tan^{-1}[\frac{e^{2x}}{5} ] +  C

3 0
3 years ago
Write a power represented with a positive base and a positive exponent whose value is less than the base
Murrr4er [49]
That's <u>always</u> true if <em>either</em> the exponent <em>or </em>the base is less than ' 1 '.

(But not always of they both are.)
7 0
3 years ago
Help me please urgent
asambeis [7]

Let \:  x  \: be  \: the \:  number \:  of \:  hours \\ Expession: - 4.5x =  - 27\Leftrightarrow x =  \frac{ - 27}{ - 4.5}  = 6 \: hours

7 0
3 years ago
(3 points)
Snezhnost [94]

Answer:

The exponential Function is 20+12h=200.

Farmer will have 200 sheep after <u>15 years</u>.

Step-by-step explanation:

Given:

Number of sheep bought = 20

Annual Rate of increase in sheep = 60%

We need to find that after how many years the farmer will have 200 sheep.

Let the number of years be 'h'

First we will find the Number of sheep increase in 1 year.

Number of sheep increase in 1 year is equal to Annual Rate of increase in sheep multiplied by Number of sheep bought and then divide by 100.

framing in equation form we get;

Number of sheep increase in 1 year = \frac{60}{100}\times20 = 12

Now we know that the number of years farmer will have 200 sheep can be calculated by Number of sheep bought plus Number of sheep increase in 1 year multiplied by number of years  is equal to 200.

Framing in equation form we get;

20+12h=200

The exponential Function is 20+12h=200.

Subtracting both side by 20 using subtraction property we get;

20+12h-20=200-20\\\\12h=180

Now Dividing both side by 12 using Division property we get;

\frac{12h}{12} = \frac{180}{12}\\\\h =15

Hence Farmer will have 200 sheep after <u>15 years</u>.

6 0
3 years ago
A shoe store was having a back to school sale were you could buy 6 pairs of shoes for 52.62 If a large family decided to buy 3 p
Black_prince [1.1K]

Answer:

$26.31

Step-by-step explanation:

Since 3 is half of 6, 3 pairs of shoes would cost half the price.

So...

52.62/2=$26.31

6 0
2 years ago
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