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anastassius [24]
4 years ago
10

Kyleigh is making a bowl of punch. The recipe calls for 2 1/4 cups for sherbet. If she uses 1 2/3 of that amount, will she be us

ing more than, less than, or the same amount of sherbet?
Mathematics
1 answer:
ankoles [38]4 years ago
3 0
Less than the original amount of sherbet
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The sixteen pack because $6.24 divided by 16 is 0.39 per dinner roll
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72 ounces in 6 steaks
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The unit rate is the total ounces divided by the total number of steaks:

72 ounces / 6 steaks = 12 ounces per steak.

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Prove
Dennis_Churaev [7]

\frac{ \sin(a) -  \cos(a)  + 1 }{ \sin(a) +  \cos(a)  - 1 }  =  \\

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\frac{ \sin(a) -  \cos(a)  + 1 }{ \sin(a) +  \cos(a) - 1  }  \times  \frac{ \sin(a)  +  \cos(a)  + 1}{ \sin(a) +  \cos(a) + 1 }  =

\frac{ {sin}^{2}(a) + 2 \sin(a)  -  {cos}^{2} (a) + 1 }{ {sin}^{2}(a) + 2 \sin(a) \cos(a)  +  {cos}^{2}(a) - 1   }  =

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As you know :

{sin}^{2} (a) +  {cos}^{2} (a) = 1

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\frac{ {sin}^{2} (a) -  {cos}^{2}(a) + 2 \sin(a)   + 1}{ {sin}^{2} (a) +  {cos}^{2}(a) - 1 + 2 \sin(a)  \cos(a)  }  =

\frac{ {sin}^{2}(a) - (1 -  {sin}^{2}(a)) + 2 \sin(a) + 1   }{1 - 1 + 2 \sin(a)  \cos(a) }  =

\frac{ {sin}^{2} (a) +  {sin}^{2} (a) - 1 + 1 + 2 \sin(a) }{2 \sin(a) \cos(a)  }  =

\frac{2 {sin}^{2}(a) + 2 \sin(a)  }{2 \sin(a) \cos(a)  }  =

\frac{2 \sin(a)( \sin(a)  + 1) }{2 \sin(a)( \cos(a) \:  ) }  =  \\

\frac{ \sin(a)  + 1}{ \cos(a) }  \\

And we're done...

Take care ♡♡♡♡♡

6 0
2 years ago
Alexis bought 1/2 pound grapes. How many ounces of grapes did she buy? Dan drew the number line below to slice the problem he sa
lorasvet [3.4K]

Answer:

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To solve the exercise the first thing is to find the equivalence between pound and ounce.

We know that 1 pound equals 16 ounces. In this exercise we have 1/2 pounds, that is, half a pound or 0.5 pounds, therefore:

1/2 pound * 16 ounces / 1 pound = 8 ounces

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7 0
3 years ago
3B. To figure out a special number, Tammi’s mother was supposed to double her age and then add 4. Instead, Tammi’s mother added
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Answer:

98

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