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Anastaziya [24]
3 years ago
11

I need help What number is 75% of 140????

Mathematics
1 answer:
Tanya [424]3 years ago
7 0

75% of 140 is 105 I hope this helps!

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Carol has 1 5/8 cups of yogurt to make smoothies. Each smoothie uses 1/3 cup of yogurt. What is the maximum number of smoothies
Mashutka [201]

Answer:

The maximal number of smothies that Carol can make with the yogurt is 4.

Step-by-step explanation:

Divide the number of cups Carol has by the number of cups needed to make one smoothie.

1\dfrac{5}{8}:\dfrac{1}{3}=\dfrac{13}{8}\cdot \dfrac{3}{1}=\dfrac{39}{8}=4\dfrac{7}{8}.

The maximal number of smothies that Carol can make with the yogurt is 4.

6 0
3 years ago
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What is the answer to this??
Helga [31]

Since the triangle is equilateral, all its angles are equal to 60°

AO is the bisector⇒∠OAD = 30°

AO AO is the hypotenuse, ∠OAD = 30°⇒

OD=10:2=5ft

By the Pythagorean theorem

10^2=AD^2+5^2\\AD=\sqrt{100-25} \\AD=\sqrt{75}

AC=AD+DC=2\sqrt{75}=10\sqrt{3}

S=\frac{a^2\sqrt{3} }{4}

S=\frac{(10\sqrt{3})^2\sqrt{3}  }{4} =\frac{300\sqrt{3} }{4} =75\sqrt{3} ft^2

Answer: A) S=75\sqrt{3}ft²

P.S. Hello from Russia and sorry for my bad english :^)

5 0
4 years ago
Zander wants to find out what the most popular sporting event is in the district’s high schools. He surveys a sample of the popu
Leokris [45]

Answer:

Surveying a sample would be valid if the population contains a diverse group of people.

7 0
3 years ago
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Please Help!!!......<br>​
valina [46]
3?
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3 years ago
Find the inverse of the given​ matrix, if it exists.Aequals=left bracket Start 3 By 3 Matrix 1st Row 1st Column 1 2nd Column 0 3
BabaBlast [244]

Answer:

A^{-1}=\left[ \begin{array}{ccc} \frac{1}{9} & \frac{4}{27} & - \frac{2}{27} \\\\ \frac{8}{9} & \frac{5}{27} & \frac{11}{27} \\\\ - \frac{4}{9} & \frac{2}{27} & - \frac{1}{27} \end{array} \right]

Step-by-step explanation:

We want to find the inverse of A=\left[ \begin{array}{ccc} 1 & 0 & -2 \\\\ 4 & 1 & 3 \\\\ -4 & 2 & 3 \end{array} \right]

To find the inverse matrix, augment it with the identity matrix and perform row operations trying to make the identity matrix to the left. Then to the right will be inverse matrix.

So, augment the matrix with identity matrix:

\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 4&1&3&0&1&0 \\\\ -4&2&3&0&0&1\end{array}\right]

  • Subtract row 1 multiplied by 4 from row 2

\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ -4&2&3&0&0&1\end{array}\right]

  • Add row 1 multiplied by 4 to row 3

\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&2&-5&4&0&1\end{array}\right]

  • Subtract row 2 multiplied by 2 from row 3

\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&0&-27&12&-2&1\end{array}\right]

  • Divide row 3 by −27

\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]

  • Add row 3 multiplied by 2 to row 1

\left[ \begin{array}{ccc|ccc}1&0&0&\frac{1}{9}&\frac{4}{27}&- \frac{2}{27} \\\\ 0&1&11&-4&1&0 \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]

  • Subtract row 3 multiplied by 11 from row 2

\left[ \begin{array}{ccc|ccc}1&0&0&\frac{1}{9}&\frac{4}{27}&- \frac{2}{27} \\\\ 0&1&0&\frac{8}{9}&\frac{5}{27}&\frac{11}{27} \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]

As can be seen, we have obtained the identity matrix to the left. So, we are done.

6 0
3 years ago
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