Answer:
The outer circle is 16 feet larger than the inner circle (68 - 52).
Step-by-step explanation:
Given that the inner circle circumference is 52 feet, and the distance between the inner and the outer circle is 8 feet, to determine by how many ft is the larger outer circle, the following calculation must be performed:
The radius of a circle is equal to half its diameter. Therefore, the radius of the inner circle is 26 feet. Thus, if the distance between the two circles is 8 feet, the radius of the outer circle is 34 feet (26 + 8). Therefore, the diameter of this circle is 68 feet (34 x 2).
This implies that the outer circle is 16 feet larger than the inner circle (68 - 52).
AC and DB are the same length. Set the two to equal each other and solve for y.
9y + 1 = 8y +17
Subtract 8y from both sides:
y + 1 = 17
Subtract 1 from each side:
y = 16
Now you know Y you can find the the length of DB:
DB = 8y +17 = 8(16) +17 = 128 + 17 = 145
EB is half of DB:
EB = 145 / 2
EB = 72.5
Answer:
on the image
Step-by-step explanation:
sorry for handwriting lol, hope this helps
Answer:
B
Step-by-step explanation:
