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Alenkasestr [34]
3 years ago
14

Please help!!!!! i’m struggling so much

Mathematics
1 answer:
Jlenok [28]3 years ago
6 0

The answer is 6.0~~~~~

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2w - 15w - 18 = -83 solve for w simplify as much as possible
Vesna [10]

Answer:

w = 5

Step-by-step explanation:

2w - 15w - 18 = -83

combine w on left side:

-13w - 18 = -83

add 18 to both sides:

-13w - 18 + 18 = -83 + 18

-13w = -65

divide both sides by -13:

-13w/-13 = -65/-13

w = 5

4 0
1 year ago
Jock decided to swim 10 km up Bega River. He swam 2 km every hour, then floated on his back for 10 minutes. Each time he floated
lara31 [8.8K]
Effectively Jock gets 1km further every round of 1:10 hrs. After 8 rounds he has reached 8km (after just having floated back from 9 to 8). The next round he completes the journey without floating.

So total 9 hours of swim and 8*10 minutes of float, that's 10 hours and 20 minutes.
3 0
3 years ago
How do you find the p and a in the graph when you know the focus and the directrix?
irina [24]
Make use of the formulas that relate p and a to the focus and directrix. Fill in the values you know and solve for the remaing one(s).
8 0
3 years ago
Write the expression as a single natural logarithm;<br> 3 ln 3 + 2 ln x
crimeas [40]

Answer:

ln (27 x²)

Step-by-step explanation:

Given in the question an expression

3 ln 3 + 2 ln x

Step1

Apply power rule

mlnx=lnx^{m}

ln 3³ +  ln x²

Step2

Apply multiplication rule

lnx + lny=ln(xy)

ln (3³ . x²)

3³ = 27

so

ln (27x²)

4 0
3 years ago
Read 2 more answers
NO LINKS!! Please help with questions 3 and 4​
Taya2010 [7]

Answer:

\textsf{3.} \quad (x,y) \rightarrow (x-5,y+2)

\textsf{4.} \quad (x,y) \rightarrow (x+3,y+1)

Step-by-step explanation:

<h3><u>Question 3</u></h3>

Given vertices of ΔLMN:

  • L = (1, -1)
  • M = (4, 1)
  • N = (5, -1)

Given vertices of ΔL'M'N':

  • L' = (-4, 1)
  • M' = (-1, 3)
  • N' = (0, 1)

From inspection of the given diagram, we can see that the two triangles are congruent since their corresponding angles and corresponding side lengths are the same.  

There is no apparent reflection or rotation, so the transformation of ΔLMN to ΔL'M'N' is by translation.

To find the mapping rule for the translation, choose one pair of corresponding vertices and determine the difference between the x and y values of the translated point and the original point:

x_{M'}-x_M =-1-4=-5 \implies \textsf{5 units left}

y_{M'}-y_M =3-1=2 \implies \textsf{2 units up}

Therefore, the mapping rule for the translation is:

(x,y) \rightarrow (x-5,y+2)

<h3><u>Question 4</u></h3>

Given vertices of ΔLMN:

  • L = (-6, -4)
  • M = (-5, -1)
  • N = (-2 -4)

Given vertices of ΔL'M'N':

  • L' = (-3, -3)
  • M' = (-2, 0)
  • N' = (1, -3)

From inspection of the given diagram, we can see that the two triangles are congruent since their corresponding angles and corresponding side lengths are the same.  

There is no apparent reflection or rotation, so the transformation of ΔLMN to ΔL'M'N' is by translation.

To find the mapping rule for the translation, choose one pair of corresponding vertices and determine the difference between the x and y values of the translated point and the original point:

x_{L'}-x_L =-3-(-6)=3 \implies \textsf{3 units right}

y_{L'}-y_L =-3-(-4)=1 \implies \textsf{1 units up}

Therefore, the mapping rule for the translation is:

(x,y) \rightarrow (x+3,y+1)

8 0
1 year ago
Read 2 more answers
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