The concentration of ca 2 in blood plasma in equivalent if its concentration is 0.0080.
Concentration means the amount of or parts in terms of the alternative components. For acid–base reactions, the equivalent weight of an acid or base is the mass which materials or reacts with one mole of hydrogen
In chemistry, equal weight (additionally known as gram equal is the mass of 1 equivalent, that is the mass of a given substance as a way to integrate with or displace a fixed amount of any other substance. The equivalent weight of an detail is the mass which combines with or displaces 1.008 gram of hydrogen or eight. Zero grams of oxygen or 35.five grams of chlorine. those values correspond to the atomic weight divided through the usual valence for oxygen as example that is sixteen.
Charge on one Ca 2+ ion = + 2 .
Concentration of calcium ion = 0.0040M
⇒ Concentration of Ca 2 + in blood plasma = 0.0040 × 2
= 0.0080 equivalent Ca 2 answer
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Answer:
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The Nernst equation is:
E = E° - RTlnK/nF
where
E° is the standard potential voltage
R is the universal gas constant = 8.314 J/mol·K
K is the reaction quotient
n is the number of moles electrons transferred
F is Faraday's constant = 96,500 C/mol e⁻
Let's determine K first. The overall reaction is:
Fe(s) + Cd²⁺(aq) --> Fe²⁺(aq) + Cd(s)
Accounting for aqueous phases only,
K = [products]/[reactants] = [Fe²⁺]/[Cd²⁺] = 0.10 M/1.4 M = 1/14
From the reactions written, you can see that 2 electrons were transferred. So, n = 2.
Lastly, the value for E⁰ is the sum of individual E⁰ of the reactions.
E⁰ = E⁰cathode - E⁰anode
Cathode reaction: Fe(s) --> 2e + Fe²⁺ (E⁰cathode = 0.44 V)
Anode reaction: Cd²⁺ + 2e --> Cd(s) (E⁰anode = -0.4 V)
Thus,
E⁰ = 0.44 - -0.4 = 0.84 V
Substituting the values (assume T at room temperature = 298 K),
E = 0.84 - (8.314)(298 K)(ln 1/14)/(2)(96,500)
<em>E = 0.87 V</em>
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