Write the equation for the formation of ethyl acetate from ethanol and acetic acid
1 answer:
The equation for the formation of ethyl acetate from ethanol and acetic acid will be ⇔
.
When ethanol reacts with acetic acid then it will form ethyl acetate.
Ethyl acetate was created through the esterification reaction between acetic acid and ethanol because once sulphuric acid would be present. Esterification is just the process by which a carboxylic acid reacts with an alcohol to create an ester.
In a chemical process known as acetoacetic ester synthesis, ethyl acetoacetate would be alkylated at the -carbon between both carbonyl groups before being transformed into a ketone, or more precisely, acetone with a -substituted carbon.
Therefore, the equation for the formation of ethyl acetate from ethanol and acetic acid will be ⇔
.
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Answer: 7.8 moles of NaCl result from the complete reaction of 3.9 mol of
Explanation:
To calculate the moles :
As is the excess reagent,
is the limiting reagent as it limits the formation of product.
According to stoichiometry :
1 mole of gives = 2 moles of
Thus 3.9 moles of will give=
of
7.8 moles of NaCl result from the complete reaction of 3.9 mol of