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2 years ago

Solve for x…………………….

Mathematics

2 answers:

natulia [17]2 years ago

7 0

Answer: first option

Step-by-step explanation:

Degger [83]2 years ago

4 0

Loading your answer Internet Problem.

Okay give the answer..

PLEASE WAIT!!!...

Answer is Option (a).

Here is your answer...

$3 {x}^{2} - 10 = - 5$

$3 {x}^{2} - 10 + 5 = 0$

$3 {x}^{2} - 5 = 0$

$3 {x}^{2} = 5$

${x}^{2} = \frac{5}{3}$

x = ± $\frac{ \sqrt{5} }{3}$

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X^2-6x+9=0 I need help

Alexxx [7]

Answer:

We have the quadratic $x^{2} - 6x + 9$ which can factor into $\boxed{(x - 3)(x - 3)}$

Hope this helps!

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3 years ago

Can someone plz help me with dis i will give brainliest

Reil [10]

Answer:

first one: B and C

Second one: x=12, y=10 so the answer is B.

Step-by-step explanation:

First one: Irrational numbers are any numbers that go on forever in the decimal without ever repeating. Any square roots of numbers that aren't perfectly square, such as 4 and 9, are irrational. And anything with pi, or $\pi$ , is always irrational.

Second one: 144 and 100 are perfect squares, meaning it can be created by multiplying the same number by itself, in this case 12 and 10. Subtract those and you get 2.

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3 years ago

Read 2 more answers

Riku took a survey to help her predict the winner of the election for student council president. She asked 40 random students in

8_murik_8 [283]

Answer:

Lynn = 28

Malcolm = 31

Tamara = 37

John = 24

Riku should predict that Tamara will win

Step-by-step explanation:

It izz wat it izzzz!!! :)

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3 years ago

-21+(-59) what is the answer

Lemur [1.5K]

Answer:

-80

Step-by-step explanation:

4 0

3 years ago

F(x)=x^3+ax^2+bx+3 where a and b are constants. bx Given that when f (x) is divided by (x+2) the remainder is 7, (a) show that 2

Vlad1618 [11]

Part I - First synthetic division

You need to use synthetic division to come up with an expression for a and b:

(x + 2) is a factor, and the remainder is 7, so we can draw a synthetic division table...

coefficients = 1 for X^3; A for X^2; B for X^1; and 3

-2 | 1 A B 3

 -2 -2(A-2) 4(A-2)-2B

 1 (A-2) -2(A-2)+B 4(A-2)-2B + 3

Remainder = 7

So...

4(A-2)-2B + 3 = 7

4 * (A - 2) - 2B + 3 = 7

4A - 8 - 2B = 4

4A - 2B = 12

2A - B = 6
Proved

-------------------------------------------------------------------------------------------------------------------
Part II - Second Synthetic Division

We draw another synthetic division table, this time with (x - 1), so the number on the left hand side will be +1

1 | 1 A B 3

 1 (A+1) A+B+1

 1 (A+1) A+B+1 A+B+4

 Remainder = 4

So...

A + B + 4 = 4

A + B = 0

A = -B

-------------------------------------------------------------------------------------------------------------------
Part III - Solving for A and B with our two simultaneous equations

We know that A = -B and we also know that 2A - B = 6

Since we know that A is equal to -B We can substitute in A for -B, to get:

2A - B = 6

Therefore...

2A + A = 6

3A = 6

A = 2

Again, as we know that A = -B, and as we have found that A = 2, we can see:

A = -B

Therefore...

2 = -B

B = -2

So our final answer is A = 2, B = -2

Hopefully this answer is more useful than the last one, and isn't so confusing!

8 0

3 years ago