3M^2 + 11MN + 6N^2 = 3M^2 + 2MN + 9MN + 6N^2
= M(3M + 2N) + 3N(3M + 2N) = (3M + 2N)(M + 3N)
Answer: 3M^2 + 11MN + 6N^2 = (3M + 2N)(M + 3N)
Answer:
Step-by-step explanation:
Switch sides:
Subtract r from both sides:
Divide both sides by p:
Sale price = 187500
20% down = 0.2 * 187500 = 37500
Loan amount = 187500-37500 = 150000
Interest = 4.65%/12 per month
Monthly payment = $1575
At the end of the first month, outstanding amount
= loan * interest rate - monthly payment
= 149006.25
Interest accrued during the first month
=150000*0.0465/12
= 581.25
Interest accrued during the second month
= outstanding amount at the end of the first month * (0.0465/12)
= 577.40
Total interest accrued during the first two months
= 581.25+577.40
= 1158.65 (to the nearest cent)
Answer:
<h2>39,991</h2>
Step-by-step explanation:
The formula of a sum of a geometric sequence:
We have
Substitute: