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jenyasd209 [6]
2 years ago
13

Х Х Work out (6 * 10%) = (3 10-) Give your answer in standard form.

Mathematics
1 answer:
Komok [63]2 years ago
7 0

here is the process hope it helps you

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Victor has 2 fraction models.Each is divided into equal sized sections the models are shaded to represent the same fraction.Mode
QveST [7]

Answer:

Model B has 6 shaded sections

Step-by-step explanation:

The question is not complete. The complete question should be in the form:

Victor has 2 fraction models. Each is divided into equal sized sections the models are shaded to represent the same fraction. Model A is divided into 6 sections and 3 sections are shaded. Model B is divided into 12 sections. What do you know about the number of sections shaded in Model B? Explain your answer.

Solution:

The fraction modeled by model A is given by the ratio of shaded sections to  the total number of sections.

That is Fraction of model A = number of shaded sections / total number of sections.

Hence:

Fraction of model A = 3 / 6

Since model B and Model A are equivalent, the number of shaded sections in Model A is given by:

number of shaded sections in model B/ total number of sections in model B =  Fraction of model A

number of shaded sections in model B / 12 = 3 / 6

number of shaded sections in model B = 12 * 3/6

number of shaded sections in model B = 6

8 0
2 years ago
Find the perimeter of quadrilateral PQRS with the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3).
storchak [24]

Answer:

P=16.53\ units

Step-by-step explanation:

we know that

The perimeter of quadrilateral PQRS is equal to the sum of its four length sides

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3)

step 1

Find the distance PQ

P(2,4), Q(2,3)

substitute in the formula

d=\sqrt{(3-4)^{2}+(2-2)^{2}}

d=\sqrt{(-1)^{2}+(0)^{2}}

d=\sqrt{1}

dPQ=1\ unit

step 2

Find the distance QR

Q(2,3), R(-2,-2)

substitute in the formula

d=\sqrt{(-2-3)^{2}+(-2-2)^{2}}

d=\sqrt{(-5)^{2}+(-4)^{2}}

dQR=\sqrt{41}\ units

step 3

Find the distance RS

R(-2,-2), and S(-2,3)

substitute in the formula

d=\sqrt{(3+2)^{2}+(-2+2)^{2}}

d=\sqrt{(5)^{2}+(0)^{2}}

dRS=5\ units

step 4

Find the distance PS

P(2,4), S(-2,3)

substitute in the formula

d=\sqrt{(3-4)^{2}+(-2-2)^{2}}

d=\sqrt{(-1)^{2}+(-4)^{2}}

dPS=\sqrt{17}\ units

step 5

Find the perimeter

P=PQ+QR+RS+PS

substitute the values

P=1+\sqrt{41}+5+\sqrt{17}

P=6+\sqrt{41}+\sqrt{17}

P=16.53\ units

5 0
3 years ago
60 x 5=?<br><br> show me something cute<br><br> EX
Evgesh-ka [11]

Answer:

60×5= 0×5= 0= 6×5= 30

= 300

6 0
2 years ago
Read 2 more answers
Choose the answer based on the most efficient method as presented in the lesson. If the first step in the solution of the equati
Keith_Richards [23]
You would add x to -3x

6 0
3 years ago
Read 2 more answers
The extract of a plant native to Taiwan has been tested as apossible treatment for Leukemia. One of the chemical compoundsproduc
Gala2k [10]

Answer:

1. P(X>69)=P(Z>-1.136)=1-P(Z

2. P(X

3. P(52.6 \leq X \leq 105.4)=P(-3

Step-by-step explanation:

Assuming the value for the mean 79 and the deviation 8.8

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

2) Part a

Let X the random variable that represent the amount of collagen of a population, and for this case we know the distribution for X is given by:

X \sim N(79,8.8)  

Where \mu=79 and \sigma=8.8

We are interested on this probability

P(X>69)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>69)=P(\frac{X-\mu}{\sigma}>\frac{69-\mu}{\sigma})=P(Z-1.136)

And we can find this probability on this way:

P(Z>-1.136)=1-P(Z

3) Part b

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability on this way:

P(Z

4) Part c

We need to find first the limits for 3 deviations within the mean

\mu -3 \sigma = 79-3(8.8)=52.6

\mu +3 \sigma = 79+3(8.8)=105.4

P(52.6

And we can find this probability on this way:

P(-3

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(-3

4 0
3 years ago
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