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puteri [66]
3 years ago
13

Join Girls ♥️yoa-duyz-fmi​

Mathematics
1 answer:
puteri [66]3 years ago
3 0

Answer:

huh

Step-by-step explanation:

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Please help due today
alisha [4.7K]
77.) x= {-5, 6}
78.) x= {-4, 9}
79.) x= {5/3, 2}
80.) x= {1/9, 3}
81.) x= {-6, 18}
82.) x= {-3√3 +4, 3√3 +4}
83.) x= {-7, -3}
84.) x= {-√85 +9 /2, √85 -9 /2}
6 0
3 years ago
The radius of a circle is 6mm. What is the area of the shaded portion of the circle.
mariarad [96]

Answer:

b) 29π mm²

Step-by-step explanation:

\frac{360}{360}  - \frac{70}{360}  =  \frac{290}{360}  \\  \\\pi \:  {r}^{2} \\  =    \frac{290}{360}  \times \pi\times 6 \times 6 \\  =  29 \: \pi  \: {mm}^{2}

6 0
3 years ago
If a hexagon is worth 5 and a triangle is worth 3, what is a circle
Olegator [25]

Answer:

6

Step-by-step explanation:

Call pentagon p, circle c and triangle t

We have 2c + 2p = 2p + 2t + c

p = 5, t = 3 so

2c + 2(5) = 2(5) + 2(3) + c

2c + 10 = 10 + 6 + c

2c = 6 + c

c = 6

4 0
3 years ago
Read 2 more answers
Given: ABCD is a trapezoid, m∠1=m∠2, m∠3=m∠4, AB = CD, AC ∩ BD = O <br> Prove: m∠AOD = m∠BCD
LiRa [457]
Since AB = CD the trapezoid is isosceles, which means that ∡A = ∡D

Therefore also ∡2 = ∡3 (they are half of the congruent angles)

For the properties of parallel lines (BD and AD) crossed by a transversal (BD) we have ∡3 = ∡CBD.

Now consider triangles AOD and BCD:
∡OAD (2) = ∡ADO (3) = ∡CBD (3) = ∡CDB (4)

T<span>he sum of the angles of a triangle must be 180°, t</span>herefore:
∡AOD = 180 - ∡2 - ∡3
∡BCD = 180 - ∡3 - ∡4

∡AOD = ∡BCD because their measure is the difference of congruent angles.

6 0
4 years ago
In a bag of keys, there are 12 silver keys, 5 black keys, 11 copper keys, and 2 painted keys of various colors. One key is drawn
umka2103 [35]
The total number of keys equals:
12 + 5 + 11 + 2 = 30 keys

The probability to pick a sliver key is:
12/30 = 2/5

The probability to pick a copper key is:
11/30

Hope that helps
7 0
3 years ago
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