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gladu [14]
3 years ago
9

I NEED HELP PLEASE, THANKS! :) Use the graph to determine the domain and range of the relation, and state whether the relation i

s a function.

Mathematics
1 answer:
Mandarinka [93]3 years ago
3 0

Answer:

Domain: All numbers greater than or equal to 0. By definition, the domain of a graph, is the possible x values.

Range: All real numbers. By definition, the range is all possible x values.

Not a function. A function has y value for every x value.

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Sally examined the three triangles pictured below. What is a possible conjecture
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Answer:

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Jaimie ran 3 1/2 miles on Monday she ran half as far on Tuesday as she did on Monday how far did Jaimie run in all on Monday and
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Determine what type of model best fits the given situation:
lyudmila [28]

Let value intially be = P

Then it is decreased by 20 %.

So 20% of P = \frac{20}{100} \times P = 0.2P

So after 1 year value is decreased by 0.2P

so value after 1 year will be = P - 0.2P (as its decreased so we will subtract 0.2P from original value P) = 0.8P-------------------------------------(1)

Similarly for 2nd year, this value 0.8P will again be decreased by 20 %

so 20% of 0.8P = \frac{20}{100} \times 0.8P = (0.2)(0.8P)

So after 2 years value is decreased by (0.2)(0.8P)

so value after 2 years will be = 0.8P - 0.2(0.8P)

taking 0.8P common out we get 0.8P(1-0.2)

= 0.8P(0.8)

=P(0.8)^{2}-------------------------(2)

Similarly after 3 years, this value P(0.8)^{2} will again be decreased by 20 %

so 20% of P(0.8)^{2}  \frac{20}{100} \times P(0.8)^{2} = (0.2)P(0.8)^{2}

So after 3 years value is decreased by (0.2)P(0.8)^{2}

so value after 3 years will be = P(0.8)^{2}   - (0.2)P(0.8)^{2}

taking P(0.8)^{2} common out we get P(0.8)^{2}(1-0.2)

P(0.8)^{2}(0.8)

P(0.8)^{3}-----------------------(3)

so from (1), (2), (3) we can see the following pattern

value after 1 year is P(0.8) or P(0.8)^{1}

value after 2 years is P(0.8)^{2}

value after 3 years is P(0.8)^{3}

so value after x years will be P(0.8)^{x} ( whatever is the year, that is raised to power on 0.8)

So function is best described by exponential model

y = P(0.8)^{x} where y is the value after x years

so thats the final answer

3 0
3 years ago
10 POINTS PLEASE HELP!!! IT SEEMS EASY BUT I DONT UNDERSTAND!!!!
Leni [432]
Hello there!

I’m not sure if they want me to add the answers together or just do them separately.

Exponents
(-2)^2=(-2)(-2)=4
(7/6)^2=7/6(7/6)=49/36

I hope this helps!
Best wishes.
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