Answer: the bridge is 11.025 m high
Step-by-step explanation:
Given that;
Time taken to hit the water t = 1.5 sec
height of bridge = ?
lets take a look at the equation of motion;
y(t) = y₀ + (1/2)at²
with initial velocity zero and we know that acceleration due to gravidity is 9.8m/s
we substitute
y(t) = (1/2)gt² = (1/2) × 9.8 × (1.5)²
y(t) = (1/2)gt² = (1/2) × 9.8 × (1.5)²
y(1.5) = 11.025 m
Therefore, the bridge is 11.025 m high
Answer:
14
Step-by-step explanation:
20-(4+14)/3
20-(18)/3
20-6
14
Hope this helped.
A Brainliest is always appreciated.
13) Angle 1= 54 Angle 2=36
14) Angle 1=122 Angle 2=58
15) Angle 1=51 Angle 2=39
Attached is the work
Hope this helps!
Answer:
k = 6
Step-by-step explanation:
14k=84
k = 84/14
k = 6
to check the equation:
14k ..we found that k is 6, so replace k with 6
14(6)
84 ......checked.
