Answer:
$36
Step-by-step explanation:
I = Prt
P = 200
r = 0.09
t = 24/12 = 2
I = 200 x 0.09 x 2
I = 36
Answer:
0.4
Step-by-step explanation:
did it in khan
The answer is : t= 4 , -3
The tangent vector is by definition the derivative of r(t) with respect to t:
<span>T' = dr/dt = <6t, tsin(t), tcos(t)> </span>
<span>The unit vector T = T'/|T'| = <6t, tsin(t), tcos(t)>/sqrt(36t^2 + t^tsin(t)^2 +t^2cos(t^2)) </span>
<span>T = <6t, tsin(t), tcos(t)>/(t*sqrt(37)) = <6, sin(t), cos(t)>/sqrt(37) </span>
<span>Now the normal unit vector N is perpendicular to r/|r| and T. It is the second derivative of r/|r| with repsect to time </span>
<span>N' = d^2r/dt^2 = <6, sin(t) + tcos(t), cos(t) - tsin(t)> </span>
<span>N= N'/|N'| = <6, sin(t) + tcos(t), cos(t) - tsin(t)>/sqrt(36 + sin^2t +2tsin(t)cos(t)+t^2cos^2t + cos^2(t) -2tcos(t) sin(t) +t^2sin^2t) </span>
<span>N = <6, sin(t) + tcos(t), cos(t) - tsin(t)>/sqrt(37 +t^2)</span>
