3 years ago

I have to do Oder of operation and I need to show my work for all 10 questions so can someone help me?

Mathematics

1 answer:

Feliz [49]3 years ago

3 0

Answer:

Order of Operations:

Parenthesis

Exponents

Multiplication

Division

Addition

Subtraction

Step-by-step explanation:

You might be interested in

Vicki and Tamra are working on their math homework together. Vicki has worked p problems, and Tamra has worked 4 times as many p

Marrrta [24]

Answer: 6

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

If it snows tomorrow, then my dentist appointment will be canceled. If my dentist appointment is canceled, then I will clean und

Dmitry_Shevchenko [17]

Yes this is a Law of Detachment.

8 0

3 years ago

Read 2 more answers

Find the area of the trapezoid shown.<br><br> 56 sq. units<br> 56√3 sq. units<br> 112 sq. units

kolbaska11 [484]

Answer: A.56 sq. units

Step-by-step explanation:

A=( a+b)h/2

(12+16)4/2

(28)2

A=56

5 0

2 years ago

Read 2 more answers

An invitation is a kind of business letter

bezimeni [28]

No its not am sure its not

4 0

3 years ago

Read 2 more answers

The length of the hypotenuse of a right angled triangle exceeds the length of the base by 2cm and exceeds twice the length of th

insens350 [35]

Answer: a = 8; b = 15; c = 17

Step-by-step explanation:

c = b + 2 and c = 2a + 1

b = c − 2 and a = $\frac{c-1}{2}$

c² = b² + a²

$c^{2} = (c-2)^{2} + \frac{c-1}{2}\\$

$c^{2}= \frac{4 (c-2)^{2}+(c - 1)^{2} }{4}$

$4c^{2}={4 (c^{2} + 4 -4c)+c ^{2} + 1-2c$

$4c^{2}={4 c^{2} + 16 -16c)+c ^{2} + 1-2c$

$c^{2}-18c+17=0$

$c(c -17)-1(c-17)=0$

$(c -1)(c-17)=0$

c = 1 or c = 17

If c = 1 then b = 1 - 2 = -1, that's not possible

So x = 17

b = 17 - 2 = 15

a = $\frac{17-1}{2} = 8$

Length sides of the triangle are 17 cm, 15 cm and 8 cm.

I saw some of this on a site but I want to make sure its correct so we're gonna apply the pythagorean theory and see if its correct.

$a^{2} + b^{2} = c^{2} \\8^{2} + 15^{2} = 17^{2} \\64 + 225 = 289\\289 = 289\\$

This shows that this is correct.

Hope this helped! Again, some of this was from a site, not from me.

3 0

2 years ago