1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
VikaD [51]
2 years ago
10

-4.56 × 10-3 in standard form.

Mathematics
1 answer:
MissTica2 years ago
5 0

Answer:

-48.6

Step-by-step explanation:

You might be interested in
Find the first four terms of this geometric sequence for a1=3 and r=-3
Natali5045456 [20]
a_1=3;\ r=-3\\\\a_2=a_1r\to a_2=3\cdot(-3)=-9\\\\a_3=a_2r\to a_3=-9\cdot(-3)=27\\\\a_4=a_3r\to a_4=27\cdot(-3)=-81\\\\Answer:\{3;-9;\ 27;-81\}
8 0
3 years ago
(1/4)^(2m)=64^m <br> Help please
Marrrta [24]

Answer:

I think the answer is m = 0

Step-by-step explanation:

2^(-4m) = 2^(6m)   set the exponent equal

- 4m = 6m   Move variable to the left

- 4m- 6m = 0   collect like terms

- 10m = 0   Divide both sides by - 10

m = 0

8 0
3 years ago
The function g(x) = x2 is transformed to obtain function h:
Westkost [7]
I think B is correct
8 0
3 years ago
Read 2 more answers
Rewrite the following fractions as division problems. a. 7⁄11 b. 5⁄2 c. 9⁄10 d. 7⁄15
d1i1m1o1n [39]
To rewrite the fractions as a division problem, use the denominator to divide the numerator. The denominator is the number below while the numerator is the number above.
1. For 7/11
Proceed as follows:
How many time will you find 11 in 7? This is not possible, so you will write down zero and put a decimal point in front of it. Then add zero at the back of 7 to get 70. How many time will 11 go in 70? That will be 6 times and you will have 4 remaining. Add zero to the back of the 4 to get 40. How many time will 11 go in 40? That will be 3 times and 7 will remain. You can continue to add zero to the remainder until you get as many decimal place as you desired.
From the calculations done above the answer we have obtained is 0.63.
Therefore, 7/11 = 0.63.

2. For 5/2, the same principle is applicable.
How many times will 2 go in 5? That will be 2 times remaining 1. Add zero to that one to obtain 10. How many times will 2 go in 10.That will be 5 times remaining zero.
Therefore 5/2 = 2.50.

3. For 9/10
How many times will 10 go in 9? That is not possible, so you will write down zero and put a decimal point in front of it. Add zero to 9 to obtain 90. How many times will 10 goes in 90. That will be 9 times exactly .
 Therefore, 9/10 = 0.90.

4.  For 7/15
How many time will 15 go in 7? That is not possible, so you write down zero with a decimal point in front of it. Add zero to 7 to get 70. How many times will 15 go in 70? That will be 4 times remaining 10. Add zero to the remaining 10 to obtain 100. How many time will 15 go in 100? That will be will be 6 times, remaining 10.
Therefore, 7/15 = 0.46
7 0
3 years ago
Read 2 more answers
Can someone answer this for me i need both answers
Shkiper50 [21]

Answer:vertex (-2,-12) and the equation y = 2 x ^2 + 8 x − 4


Step-by-step explanation:


3 0
3 years ago
Other questions:
  • Which of the following describes a compound
    6·1 answer
  • Four more than the quotient of a number and 3 is 2
    10·1 answer
  • 84/12 = 28/x 1. x=4 2. X=28
    7·1 answer
  • Which is the graph of f(x) = (2) ^-x
    9·1 answer
  • Name the coordinates of point K after its is reflected over the y-axis
    8·1 answer
  • Please help me! im literally desperate! math is soooo hard! help me pls &lt;3
    5·1 answer
  • A Normal distribution has mean µ = 61.6. Find it’s standard deviation if 20% of the values are greater than 70. (Hint--use the z
    8·1 answer
  • What is the difference between a terminating decimal and a repeating decimal?​
    6·1 answer
  • Four friends bought tickets to the school play. If it cost then a total of $28, Which equation could be used to find how much ea
    13·1 answer
  • PLS HELP ASAP I FORGOT PLS NO BOT LINKS
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!