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2 years ago

Find sin(α) in the triangle.

Mathematics

1 answer:

cluponka [151]2 years ago

6 0

$\frac{20}{29}$ Answer:

sin α = $\frac{20}{29}$

Step-by-step explanation:

sin α = $\frac{opposite}{hypotenuse}$ = $\frac{BC}{AB}$ = $\frac{20}{29}$

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Step-by-step explanation:

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Read 2 more answers

The area of ABED is 49 square units. Given AGequals9 units and ACequals10 units, what fraction of the area of ACIG is represent

stiks02 [169]

Answer:

The fraction of the area of ACIG represented by the shaped region is 7/18

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

In the square ABED find the length side of the square

we know that

AB=BE=ED=AD

The area of s square is

$A=b^{2}$

where b is the length side of the square

we have

$A=49\ units^2$

substitute

$49=b^{2}$

$b=7\ units$

therefore

$AB=BE=ED=AD=7\ units$

step 2

Find the area of ACIG

The area of rectangle ACIG is equal to

$A=(AC)(AG)$

substitute the given values

$A=(9)(10)=90\ units^2$

step 3

Find the area of shaded rectangle DEHG

The area of rectangle DEHG is equal to

$A=(DE)(DG)$

we have

$DE=7\ units$

$DG=AG-AD=9-7=2\ units$

substitute

$A=(7)(2)=14\ units^2$

step 4

Find the area of shaded rectangle BCFE

The area of rectangle BCFE is equal to

$A=(EF)(CF)$

we have

$EF=AC-AB=10-7=3\ units$

$CF=BE=7\ units$

substitute

$A=(3)(7)=21\ units^2$

step 5

sum the shaded areas

$14+21=35\ units^2$

step 6

Divide the area of of the shaded region by the area of ACIG

$\frac{35}{90}$

Simplify

Divide by 5 both numerator and denominator

$\frac{7}{18}$

therefore

The fraction of the area of ACIG represented by the shaped region is 7/18

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3 years ago

Which one is right please explain

Kitty [74]

The correct answer would be B. Hope this helps, and please mark me the brainliest, we can be friends!!

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3 years ago

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Montano1993 [528]

Work=speed times time (my equation to help me figure it out)

ok, 10 men take 84 days to complete a job
therefor, each man completes 1/10 of the job in 84 days
each man does 1/840 of the job per 1 day

so, if we had 5 more, or 15 men

15 times 1/840 times xdays=1 job complete
15/840 times xdays=1job
times both sides by 840/15
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3 years ago