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2 years ago

Help quicksubtract a³+b³-3 from the sum of 2a³-3b³+7 and -a³+b³+3ab-a

Mathematics

2 answers:

frez [133]2 years ago

5 0

Answer:

-3b³ + 3ab - a + 10

Step-by-step explanation:

2a³ - 3b³ + 7 - a³ + b³ + 3ab - a - (a³+b³-3)

2a³ - 3b³ + 7 - a³ + b³ + 3ab - a - a³ - b³ + 3

-3b³ + 3ab - a + 10

lora16 [44]2 years ago

4 0

Solution:

<u>Simplify the expression and solve.</u>

{(2a³- 3b³ + 7) + (-a³ + b³ + 3ab - a)} - {a³ + b³ - 3}
=> {2a³- 3b³ + 7 - a³ + b³ + 3ab - a} - a³ - b³ + 3
=> {a³- 2b³ + 7 + 3ab - a} - a³ - b³ + 3
=> {a³- 2b³ + 7 + 3ab - a} - a³ - b³ + 3
=> -3b³ + 7 + 3ab - a + 3
=> -3b³ + 10 + 3ab - a

The solution to this algebraic problem is -3b³ + 10 + 3ab - a.

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Translate the sentence into an equation Twice the difference of a number and 9 is equal to 5use the variable w for the unknown n

TEA [102]

Let w the unknown number. Then, you have

$\begin{gathered} 2(w-9)\rightarrow\text{ Twice the difference of a number and 9} \\ 2(w-9)=5\rightarrow\text{Twice the difference of a number and 9 is equal to 5} \end{gathered}$

3 0

1 year ago

While her husband spent 2½ hours picking out new speakers, a statistician decided to determine whether the percent of men who en

AVprozaik [17]

Answer:

$z=\frac{p_{M}-p_{W}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{M}}+\frac{1}{n_{W}})}}$ (1)

$z=\frac{0.34848-0.34782}{\sqrt{0.34831(1-0.34831)(\frac{1}{66}+\frac{1}{23})}}=0.0057$

$p_v =P(Z>0.0057)=0.4977$

The p value is a very high value and using the significance level $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the percent of men who enjoy shopping for electronic equipment is NOT significantly higher than the percent of women who enjoy shopping for electronic equipment.

Step-by-step explanation:

1) Data given and notation

$X_{M}=23$ represent the number of men that said they enjoyed the activity of Saturday afternoon shopping

$X_{W}=8$ represent the number of women that said they enjoyed the activity of Saturday afternoon shopping

$n_{M}=66$ sample of male selected

$n_{W}=23$ sample of demale selected

$p_{M}=\frac{23}{66}=0.34848$ represent the proportion of men that said they enjoyed the activity of Saturday afternoon shopping

$p_{W}=\frac{8}{23}=0.34782$ represent the proportion of women with red/green color blindness

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to check if the percent of men who enjoy shopping for electronic equipment is higher than the percent of women who enjoy shopping for electronic equipment , the system of hypothesis would be:

Null hypothesis: $p_{M} \leq p_{W}$

Alternative hypothesis: $p_{M} > p_{W}$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{M}-p_{W}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{M}}+\frac{1}{n_{W}})}}$ (1)

Where $\hat p=\frac{X_{M}+X_{W}}{n_{M}+n_{W}}=\frac{23+8}{66+23}=0.34831$

3) Calculate the statistic

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.34848-0.34782}{\sqrt{0.34831(1-0.34831)(\frac{1}{66}+\frac{1}{23})}}=0.0057$

4) Statistical decision

Using the significance level provided $\alpha=0.05$ , the next step would be calculate the p value for this test.

Since is a one side right tail test the p value would be:

$p_v =P(Z>0.0057)=0.4977$

So the p value is a very high value and using the significance level $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the percent of men who enjoy shopping for electronic equipment is NOT significantly higher than the percent of women who enjoy shopping for electronic equipment.

4 0

3 years ago

What is the length of missing side JK? Round Answer to nearest tenth please.

zvonat [6]

Given:

Triangle LJK.

LJ = 89 in, LK = 28 in and m∠L = 42°

To find:

The length of missing side JK.

Solution:

LJ = k = 89

LK = j = 28