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mrs_skeptik [129]
4 years ago
10

The polynomial below is a perfect square trinomial of the form A^2-2AB+B^2. 9x^2-18x+36

Mathematics
2 answers:
baherus [9]4 years ago
8 0
No, It's not.

coefficients for perfect square would be:
3² - 2(3)(6) + 6² = 9 - 36 + 36

Colt1911 [192]4 years ago
4 0

Answer: false

Step-by-step explanation:

APEX

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What is 3/16 as decimals
slamgirl [31]
0.1875 you must divide 3 by 16 the numerator by the denominator
3 0
3 years ago
Help me pleae HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
max2010maxim [7]

Answer:

Step-by-step explanation:

d = c/pi

so d = 62.8/pi

    d = 62.8/pi or appr 19.99in

r = d/2

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a = \pi  r^{2}

so

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then

a = 985.96/pi

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a = approximately 313.84

answer is rowan

3 0
3 years ago
1.64 points as a mix number in simplest form
zhuklara [117]
The correct answer is 41/25
8 0
3 years ago
Assume that the wavelengths of photosynthetically active radiations (PAR) are uniformly distributed at integer nanometers in the
trasher [3.6K]

Answer:

Mean=685

Variance=36.7

Step-by-step explanation:

The mean of uniform discrete distribution can be expressed as the average of the boundaries

mean=( b+a)/2

The variance of uniform discrete distribution can be expressed as the difference of the boundaries decreased by 1 and squared, decreased by 1 and divided by 12.

σ²=[(b-a+1)^2 - 1]/12

We were given the wavelength from from 675 to 695 nm which means

a= 675, b= 695

We can now calculate the mean by using the expresion below

mean=( b+a)/2

Mean=( 675 + 695)/2

=685

The variance can be calculated by using the expression below

σ²=[(b-a+1)^2 - 1]/12

σ²=[(695-675+1)^2 -1]/12

σ²=440/12

σ²=36.7

Therefore, the the mean and variance, of the wavelength distribution for this radiation are 685 and 36.7 respectively

7 0
3 years ago
A. 46 <br> B. 72<br> C.45<br> D.36
ASHA 777 [7]

Answer: C 45

Step-by-step explanation:

7 0
3 years ago
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