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2 years ago

11

Mia has a jewelry box with a length of 6 inches, a width of 4 inches and a height of 10 inches. What is the volume of Mia's jewe

lry box?

1 answer:

RideAnS [48]2 years ago

8 0

Answer:

240

Step-by-step explanation:

volume of cubical box =l×b×h

=6×4×10

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In Marissa's calculus course, attendance counts for 20% of the grade, quizzes count for 15% of the grade, exams count for

Tema [17]

Step-by-step explanation:

20% (100) + 15% (93) + 45% (86) + 20% (81)

= 20 + 13.95 + 38.7 + 16.2

= 88.85

Her course average is 88.85% (or 89%, rounded to the nearest integer).

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4 years ago

Which choice is equivalent to the expression below?<br>√-64

Maru [420]

Answer:

The answer is option A.

√-64 = 8i

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4 years ago

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In a basket, 3 out of 4 eggs are cracked. how many eggs are cracked if their is a total of 28 eggs in the basket

Sidana [21]

Cracked:all=3:4
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21 are cracked (bad deal)

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3 years ago

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What is the height of the cylinder had a volume of 144pi and radius of 2 inches

Reptile [31]

Answer:

Step-by-step explanation:

$V=h\pi r^2\\ \\ h=\frac{V}{\pi r^2}\ V=144\pi \ r=2in\\ \\ h=\frac{144\pi }{\pi 2^2}\\ \\ h=\frac{144}{4}\\ \\ h=36in$

3 0

3 years ago

Prove that if the set of vectors {u1, u2, u3} is linearly dependent and u4 is any vector, then the set {u1, u2, u3, u4} is linea

Lesechka [4]

Answer with Step-by-step explanation:

We are given that the set of vectors ${u_1,u_2,u_3}$ is lineraly dependent set .

We have to prove that the set ${u_1,u_2,u_3,u_4}$ is linearly dependent .

Linearly dependent vectors : If the vectors $u_1,u_2.u_3,u_4$

are linearly dependent therefore the linear combination

$a_1u_1+a_2u_2+a_3u_3+a_4u_4=0$

Then ,there exit a scalar which is not equal to zero .

Let $a_1\neq0$ then the vector $u_1$ will be zero and remaining other vectors are not zero.

Proof:

When $u_1,u_2,u_3$ are linearly dependent vectors therefore, linear combination of vectors of given set

$a_1u_1+a_2u_2+a_3u_3=0$

By definition of linearly dependent vector

There exist a scalar which is not equal to zero.

Suppose $a_1\neq 0$ then $u_1=0$

The linear combination of the set ${u_1,u_2,u_3,u_4}$

$a_1u_1+a_2u_2+a_3u_3+a_4u_4=0$

When $a_1\neq0\; and\; u_1=0$

Therefore,the set ${u_1,u_2,u_3,u_4}$ is linearly dependent because it contain a vector which is zero.

Hence, proved .

5 0

3 years ago