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Nadya [2.5K]
2 years ago
11

Mia has a jewelry box with a length of 6 inches, a width of 4 inches and a height of 10 inches. What is the volume of Mia's jewe

lry box?
Mathematics
1 answer:
RideAnS [48]2 years ago
8 0

Answer:

240

Step-by-step explanation:

volume of cubical box =l×b×h

=6×4×10

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Please someone right now please 10x23-9+90(23-9)
Burka [1]

Answer:

1481

Step-by-step explanation:

8 0
2 years ago
Given the following functions, find the indicated values.
allsm [11]

Answer:

A. f(-2)=3-6(-2)

-2f =3-(-12)

-2f=3+12

=15

divide both sides by 2

f=15/2

B. f(0)=3-6(0)

f=3

C.f(4)=3-6(4)

4f=3-24

f=21/4

5 0
2 years ago
30 points! Find the four arithmetic means between -17 and 32.
bearhunter [10]

Answer: - 7.2 , 2.6 , 12.4 and 22.2

Step-by-step explanation:

Let the arithmetic means be p , q , r ,s , therefore , the sequence becomes:

-17 , p , q , r , s , 32

The first term (a ) = -17

Last term (L) = 32

common difference (d) = ?

number of terms (n ) = 6

We will use the formula for calculating the last term to find the common difference. That  is

L = a + (n - 1 ) d

Substituting the values , we have

32 = -17 + (6-1) d

32 = -17 + 5d

32 + 17 = 5d

49 = 5d

Therefore: d = 9.8

We can therefore find the values of p , q , r , and s

p is the second term , that is

p = a + d

p = -17 + 9.8

p = -7.2

q = a + 2d

q = - 17 + 19.6

q = 2.6

r = a + 3d

r = - 17 + 29.4

r = 12.4

s = a + 4d

s = - 17 + 39.2

s = 22.2

Therefore : the arithmetic means are : - 7.2 , 2.6 , 12.4 and 22.2

8 0
3 years ago
Chandra created a budget matrix based on her regular and expected expenses for the year. Expense Jan. Feb. Mar. Apr. May June Ju
Ivan

Answer:

Chandra's Average Monthly Expenses are;

1) For Both Jan and Feb are $269

2) For the remaining 10 months each are $244

Step-by-step explanation:

From Chandra's matrix all monthly expenses are all same that is,

Cell phone $71, Rent $1,025, Gym $75, Internet $25, Auto insurance $425, Gas $ 120, Food $145. which are all the expenses carried out every month for 12 months.

That means Chandra carries out a total of 7 expenses for the month of January and February while she carried a total of 6 expenses for the remaining 10 month which was noted from the matrix that Auto insurance was carried out only in the month of January and February.

Therefore, you start by adding up each month total expenses, which are ;

January = $71 + $1,025 + $75 + $25 + $425 + $120 + $145 = $1886

February = $71 + $1,025 + $75 + $25 + $425 + $120 + $145 = $1886

March = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

April = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

May = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

June = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

July= $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

August = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

September = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

October = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

November = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

December = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

Therefore Chandra's Average Monthly Expenses are:

1) January & February  = \frac{71 + 1,025 + 75 + 25 + 425 + 120 + 145}{7} = \frac{1886}{7} = 269.4286 to the nearest cent

≅ $269

2) For the remaining 10 month are = \frac{71 + 1,025 + 75 + 25  + 120 + 145}{6} = \frac{1461}{6}= 243.5 to the nearest cent

≅ $244

8 0
3 years ago
Read 2 more answers
Which equation shows the point-slope form of the line that passes through (-9, -3) and has a slope of -6?
Snowcat [4.5K]

Answer:

y=-6x-57 is your answer.

Step-by-step explanation:

You will use this equation:

y-y1=m(x-x1). The y1 is -2 and the x1 is -9.

y-(-3)=-6(x-(-9)). You will the distribute the -6 into the x and the -9.

y+3=-6x-54. You will then subtract 3 to both sides.

y=-6x-57 is your answer.  

3 0
3 years ago
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