The first thing to do is to clear the equation of fractions by multiplying by its LCM, which is 6 in this case. When you do that, you will get the equation
4p + 36 = 7p. Much easier to deal with, right? Now move the 4p over by subrtracting it: 36 = 3p, and p = 12
Let us assume for starters that it is true.
The area of the square is s^2, so that is where you start.
(1 + 2*sqrt(2) ) ^2 = 1 + 4*sqrt(2) + 8 Taking 1 away form that does not leave you with 8.
Let's start again.
If all sides are reduced by 1 , but the square is retained, then the length of the side is 2sqrt(2). Now we have
s^2 = (2sqrt(2) )^2 = 4 * 2 = 8
The question is really not worded clearly enough to give an answer. I think it's true, but the language has to be twisted a bit.
Answer: I'd answer true, but don't be surprised if it is not interpreted the way I did on my second try.
We use the Pythagorean theorem here, because we have the two sides and a right angle between them, so we calculate the hypotenuse like this:
x^2 = 6^2 + 8^2
x^2 = 36 + 64
x^2 = 100
x = square root of 100
x = 10
The correct answer is B.10.
