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Komok [63]
3 years ago
6

Which equation below has no solution?

Mathematics
2 answers:
andrew11 [14]3 years ago
8 0

Answer:

B is your answer

Step-by-step explanation:

Answer A is -2

Answer C is many solutions

Alina [70]3 years ago
3 0
B cause of both side give you 12x which would cancel out.
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What are the factors of 45
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The factors of 45 are: 1, 3, 5, 9, 15, 45

Which numbers multiply together to equal 45?
1 \times 45 = 45 \\ 3 \times 15 = 45 \\ 5 \times 9 = 45
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Which statement is true about the graphed function?
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Answer:

the last option or D

Step-by-step explanation:

f(x) > 0 over the interval (-∞, -4)

i hope this helps! quizlet is also very helpful lol, have a wonderful rest of your day/night, xx, nm <3 :)

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I need help with this. I'm stuck. PLEASE SAVE ME
vagabundo [1.1K]

Answer: Its the one.

Step-by-step explanation:

Your going to subtract 2 from each sides making the equation, -5 is less than or equal to 25, then your gonna divide -5 by 25, which will give you -5, and then the sign will switch to greater than or equal to because you divided by a negative number. The dot on the number line will be solid because the sign is greater than or equal to. You're welcome :)

7 0
3 years ago
Help me with hanger math...
andrew11 [14]
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6 0
3 years ago
Hello pls help meeee
AnnyKZ [126]

The function is (-x+3)/ (3x-2) and we get f(1)=1 and differentiation is f'(x)=-7/ (9x²- 12x+4).

Given that,

The function is (-x+3)/ (3x-2)

We have to find f(1) and f'(x).

Take the function expression

f(x)= (-x+3)/ (3x-2)

Taking x as 1 value

f(1)= (-1+3)/(3(1)-2)

f(1)=2/1

f(1)=1

Now, to get f'(x)

With regard to x, we must differentiate.

f(x) is in u/v

We know

u/v=(vu'-uv')/ v²        (formula)

f'(x)= ((3x-2)(-1)- (-x+3)(3))/ (3x-2)²

f'(x)= ((-3x+2)-(-3x+9))/ 9x²- 12x+4

f'(x)=(-3x+2+3x-9)/ 9x²- 12x+4

f'(x)=2-9/ (9x²- 12x+4)

f'(x)=-7/ (9x²- 12x+4)

Therefore, The function is (-x+3)/ (3x-2) and we get f(1)=1 and differentiation is f'(x)=-7/ (9x²- 12x+4).

To learn more about function visit: brainly.com/question/14002287

#SPJ1

6 0
1 year ago
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