Determine the area of the parallelogram with vertices (4, 6, 2), (4, 7, 2), (9, 7, 2), and (9, 8, 2). Use the square root symbol

Question

anzhelika [568]

3 years ago

12

Determine the area of the parallelogram with vertices (4, 6, 2), (4, 7, 2), (9, 7, 2), and (9, 8, 2). Use the square root symbol

'√' where needed to give an exact value for your answer.

Mathematics

1 answer:

astra-53 [7] · Answer 1 · 2022-04-03T12:17:32+03:00

Answer:

5 square units

Step-by-step explanation:

The parallelogram lies entirely in the plane z=2, so we can treat this as a 2-dimensional problem.

In the order given, the vertices do not define a parallelogram. Two of the sides are parallel, but the other two sides cross each other, for a net area of zero.

If we swap the order of the last two vertices, we get a parallelogram that has a base of 1 unit and a height of 5 units. Its area is ...

A = bh = 1·5 = 5 . . . square units