Determine the area of the parallelogram with vertices (4, 6, 2), (4, 7, 2), (9, 7, 2), and (9, 8, 2). Use the square root symbol
'√' where needed to give an exact value for your answer.
1 answer:
Answer:
5 square units
Step-by-step explanation:
The parallelogram lies entirely in the plane z=2, so we can treat this as a 2-dimensional problem.
In the order given, the vertices do not define a parallelogram. Two of the sides are parallel, but the other two sides cross each other, for a net area of zero.
If we swap the order of the last two vertices, we get a parallelogram that has a base of 1 unit and a height of 5 units. Its area is ...
A = bh = 1·5 = 5 . . . square units
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The answer is x=-80.
First subtract 4 from both sides.
-6=+4
-6-4=+4-4
-10=
Multiply 8 on both sides to isolate x.
-10·8=
-80=x
Answer:
9
Step-by-step explanation:
If first odd number is x
THen next consecutive odd number is x + 2
Next one is x + 4
Now, we can write the word problem as:
Now we solve:
So, x is less than or equal to 9, so it can be
9, 7, 5 .....
What is the maximum value of the lowest number (x)?? It is 9