I need help on 5

Use the explicit formula an = a + (n-1). d to find the 500th term of the

nadezda [96]

Answer:

Step-by-step explanation:

The difference is a2 - a1 = 31 - 24 = 7

n = 500

a500 = a1 + (500 - 1) * 7

a500 = 24 + 499 * 7

a500 = 24 + 3493

a500 = 3517

8 0

3 years ago

PLZ HELP Math show work 1. Graph the function: () = 3/2 − 4

MissTica

The answer is one in a half

7 0

2 years ago

A rectangular prism is 4 inches long, 6 inches wide, and has a height of 5 inches. What is its volume?

Strike441 [17]

I think the answer is
B.120 in3

3 0

3 years ago

Four members from a 50 person committee are to be randomly selected to serve as chairperson, vicechairperson, secretary, and tre

alexdok [17]

Answer:

So, exists 5527200 different leadership structures.

Step-by-step explanation:

We know that four members from a 50 person committee are to be randomly selected to serve as chairperson, vicechairperson, secretary, and treasurer. The first perosn to be selected is the chairperson, the second to be selected as vice chairperson, the third is secretary, and the fourth is treasurer.

Since the order of the people is important to us, we have the following:

50·49·48·47=5527200

So, exists 5527200 different leadership structures.

3 0

3 years ago

If a random sample of size nequals=6 is taken from a population, what is required in order to say that the sampling distributio

goldenfox [79]

Answer:

$\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})$

In order to satisfy this distribution we need that each observation on this case comes from a normal distribution, because since the sample size is not large enough we can't apply the central limit theorem.

Step-by-step explanation:

For this case we have that the sample size is n =6

The sample man is defined as :

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

And we want a normal distribution for the sample mean

$\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})$

In order to satisfy this distribution we need that each observation on this case comes from a normal distribution, because since the sample size is not large enough we can't apply the central limit theorem.

So for this case we need to satisfy the following condition:

$X_i \sim N(\mu , \sigma), i=1,2,...,n$