<span>10 units to the right and 2 units up,</span>
Find the inertia tensor for an equilateral triangle in the xy plane. Take the mass of the triangle to be M and the length of a side of the triangle to be b. Express your answer below as pure numbers in units of Mb^2. Place the origin on the midpoint of one side and set the y-axis to be along the symmetry axis.
Answer:
x=59 y= 81 z= 99
Step-by-step explanation:
z=
180-(57+24)=99
y=180-99=81
x= 40+81=121
180-121=59
Answer:
f = -15
Step-by-step explanation:
Answer:
the answer is C
Step-by-step explanation:
plato