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Neko [114]
2 years ago
10

Please help on this math question!!

Mathematics
1 answer:
katrin2010 [14]2 years ago
6 0

Answer:

x = 49

Step-by-step explanation:

The third side of the largest of the inner triangles:

= \sqrt{(7\sqrt{(33)^{2} }- (33)^{2}

=\sqrt{528} =\sqrt{(16)(33)} =4\sqrt{33}

The side that continues next to 33: x -33

Applying similarity property on right triangles:

\frac{33}{4\sqrt{33} } =\frac{4\sqrt{33} }{x-33}

(33)(x-33)=(4\sqrt{33} )^{2}

33x-1089=528

33x=528+1089

x=\frac{528+1089}{33} =49

Hope this helps

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Answer:

a) 0.984

b) 20 people

Step-by-step explanation:

a)

If The probability that a person carries the gene is 0.1, then in a sample of 20 people, 2 should carry the gene.

Now, we want to know how many samples there are with this property.

Since we have 20 elements where 18 are alike (do not carry the gene) and 2 are alike (carry the gene), we have to compute the number of permutations of 20 elements in which 18 are alike and 2 are alike. This number is

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(1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

(1,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

(0,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

where 1=carries the gene, 0=does not carry the gene.

So there are 190-3 = 187 elements in which the first 3 elements have no 2 carriers, hence the probability that 4 or more people will have to be tested until 2 of them with the gene are detected is 187/190 = 0.984 (98.4%) rounded to three decimal places.

b)

Given that the probability that a person carries the gene is 0.1, then in a sample of 20 people, 20*0.1 = 2 should carry the gene.

4 0
3 years ago
One year ago, you purchased 600 shares of stock for $14 a share. the stock pays $.41 a share in dividends each year. today, you
alukav5142 [94]
If you paid $14 for 600, you paid:

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The return on the investment being $780

Very very safe investment and not worth it.
5 0
4 years ago
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