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otez555 [7]
3 years ago
7

The expression 1 2 b h 2 1 ​ bhstart fraction, 1, divided by, 2, end fraction, b, h gives the area of a triangle where b bb is t

he base of the triangle and h hh is the height of the triangle. What is the area of a triangle with a base of 7 cm 7 cm7, start text, space, c, m, end text and a height of 4 cm 4 cm4, start text, space, c, m, end text?
Mathematics
1 answer:
adoni [48]3 years ago
4 0

Answer:

14cm²

Step-by-step explanation:

Area of a triangle (A) is 1/2bh where;

b is the base of the triangle

h is the height of the triangle

Given the base = 7cm and height = 4cm,

Substituting the given values into the formula of area of a triangle we have;

A = 1/2×7×4

A = 14cm²

Therefore the area of the triangle is 14cm²

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Solve 9,159 divided by 7
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(9159 / 7 = 1308.429)

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Simply multiply the last digit by 2 and then subtract the product from the remaining digits.

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915 - (9 x 2) = 897

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3 years ago
How many solutions exist for the given equation?
sladkih [1.3K]

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URGENT MATH HELP BRAINLIEST
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Answer:

Step-by-step explanation:

a. This is a right triangle with two sides and one angle given.

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\frac{a}{Sin \ A}=\frac{b}{Sin \ B}=\frac{b}{Sin \ C}

-The sides given are 10and 17 and the right angle 90°

\frac{17}{Sin \ 90 \textdegree}=\frac{10}{Sin \ m\angle B}\\\\m\angle B=Sin^{-1}\frac{10}{(17/Sin \ 90\textdegree)}\\\\=36.03\textdegree

Hence  the angle B is 36.03°

b.We again use the sine rule to obtain the unknown angle w:

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\frac{a}{Sin \ a}=\frac{b}{Sin \ B}\\\\\frac{15}{Sin \ 90\textdegree}=\frac{9}{Sin \ w\textdegree}\\\\\\\\w=Sin^{-1}(\frac{9}{15}), \ \ Sin \ 90\textdegree=1\\\\=36.87\textdegree

Hence, the measure of w is 36.87°

4 0
3 years ago
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