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GREYUIT [131]
2 years ago
8

A car accelerates at a rate of 3.0

Physics
1 answer:
ziro4ka [17]2 years ago
5 0
Force = mass x acceleration = 3000 x 3.0 = 9000 kg*m/s
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The, it's electron goes for HIGHER orbital form lower orbital
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If you apply force on an object such as a ball, what will possibly happen to it?​
alexandr402 [8]
It will move in the direction you pushed it, but it will go at a certain velocity
4 0
3 years ago
Physics class 9 chapter 8 please tell​ please
natali 33 [55]

Answer:

(a) The motion is uniform

(b)  11.11 m/s

Explanation:

(a)

From the table below, the motion of the bus is uniform.

(b)

Speed(s) = Δd/Δt

s = Δd/Δt............. Equation 1

From the table,

Given: Δd = 10 km = 10000 m, Δt = 15 minutes = (15×60) = 900 seconds

Substitute these values into equation 1

s = 10000/900

s = 11.11 m/s

7 0
3 years ago
2) The position of a particle is given r(t) = A(cos wt i + sin wt f), where w is a constant. (a) Show that the particle moves in
olya-2409 [2.1K]

Answer:

Explanation:

r(t) = A(cos wt i + sin wt f)

= A cos wt i + A sin wt j

x = A cos wt

y = A sin wt

radius r

r² = x² + y² ( This is equation of a circle with radius r  )

=  A² cos² wt +A² sin² wt

= A²

r = A

radius r = A

b )

speed = dr/dt

v = - Aw sinwt i + Aw coswt j

magnitude of velocity

I v I= Aw √(sin²wt + cos²wt)

= Aw ( constant )

acceleration

= dv / dt = - Aw² cos wt - Aw² sinwt

magnitude of acceleration

I a I = Aw²

= r w²

d ) centripetal force = m acceleration

m w² A  

=

7 0
3 years ago
What formula gives the strength of an electric field, E, at a distance from a known source charge?
Deffense [45]
<h2>Hello!</h2>

The answer is: Coulomb's law equation.

<h2>Why?</h2>

The Coulomb's law states that the strength of an electric field (between two charges) can be calculated by multiplying their charges and dividing it into the square of the distance between their centers.

E=\frac{k*q*Q}{d^{2} }

Where:

E = Electric Field Strenght

k=9.0*10^{9}  \frac{N.m^{2} }{C^{2} }

q=TestCharge\\Q=SourceCharge\\

d = separation between charges (m)

Have a nice day!

5 0
4 years ago
Read 2 more answers
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