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saveliy_v [14]
3 years ago
8

How much would a 75kg man weigh due to the effect of gravity

Physics
1 answer:
Nezavi [6.7K]3 years ago
4 0

Answer: 735 N

Explanation:

Weight W is a measure of the gravitational force acting on an object and is directly proportional to the product of the mass m of the body by the acceleration of gravity g:  

W=m.g

In the case of our planet Earth, the acceleration due gravity is g=9.8 m/s^{2}. So for a man whose mass is m=75 kg, his weight is:

W=(75 kg)(9.8 m/s^{2})

W=735 N

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An Object, Start from rest w Confront Aiceleration 8m/s2 along a
shutvik [7]

Answer:

A)   v = 40 m / s, B)   v_average = 20 m / s

Explanation:

For this exercise we will use the kinematics relations

         

A) the final velocity for t = 5 s and since the body starts from rest its initial velocity is zero

         v = vo + a t

         v = 0 + 8 5

         v = 40 m / s

B) the average velocity can be found with the relation

         v_average = vf + vo / 2

         v-average = 0+ 40/2

          v_average = 20 m / s

6 0
3 years ago
A nonconducting spherical shell, with an inner radius of 4 cm and an outer radius of 6 cm, has charge spread nonuniformly throug
Vaselesa [24]

Answer:

1.57 * 10^{3} Q

Explanation:

The volume charge density is defined by ρ = \frac{Q}{V} (Equation A), where Q is the charge and V, the volume.

The units in the S.I. are \frac{Coulombs}{m^{3} }, so we have to express the radius in meters:

inner radius = 4 cm * \frac{1 m}{100 cm} = 0.04m

outer radius = 6 cm * \frac{1m}{100cm}  = 0.06m

Now, we know that the volume of the sphere is calculated by the formula:

V = \frac{4}{3}\pi r^{3}, and as we have an spherical shell, the volume is calculated by the difference between the outher and inner spheres:

V = \frac{4}{3}\pi (r_{o} ^{3} - r_{i} ^{3}), where r_{o} is the outer radius and r_{i} is the inner radius.

Replacing the volume formula in the Equation A:

ρ = \frac{Q}{\frac{4}{3}\pi(r^{3} _{o}-r_{i} ^{3})}

ρ = \frac{3Q}{4\pi (r_{o} ^{3}-r_{i} ^{3} ) }

Replacing the values of the outer and inner radius whe have:

ρ = \frac{3Q}{4\pi (1.52 * 10^{-4})}

ρ = 1.57 * 10^{3} Q

4 0
3 years ago
Find the product of 30−−√ and 610−−√. Express it in standard form (i.
Helen [10]
The product of √30 and √610 is 10√183.


√30  = √(2×3×5)
and √610 = √(2×5×61

Since 61 can't be factorised further.
Therefore, the value of √30×√610 is
= √(2×3×5×2×5×61)
= 2×5×√(3×61)
=10√183
4 0
3 years ago
Read 2 more answers
An object experiences a 8.9 N force and accelerates 6 m/sec2. What is the object's
Inessa [10]

b stupidrwfs

planation:

3 0
3 years ago
A trombone has a variable length. When a musician blows into the mouthpiece and causes air in the tube of the horn to vibrate, t
tiny-mole [99]

Answer:

B) The frequency will increase

Explanation:

The length of the instrument is given by

L=\dfrac{\lambda}{2}\\\Rightarrow \lambda=2L

Wavelength is given by

\lambda=\dfrac{v}{f}

\dfrac{v}{f}=2L\ or\ L\propto \dfrac{1}{f}

It can be seen that the length is inversely proportional to the frequency.

Here, the length of the trombone is decreasing so the frequency will increase.

6 0
3 years ago
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