Answer:
q = 76.8*10⁻⁹ C = 76.8 nC
Explanation:
Assuming no other forces acting on the charges, and that both spheres must be considered as point charges (and as point masses as well) , the force that is responsible for the initial acceleration is the electrostatic force, which obeys Coulomb´s Law.
According to Newton´s 2nd Law, this force is related with the mass and the acceleration as follows:
This same force, expressed as the electrostatic force, is as follows:
As both expressions for F are equal each other, we can solve for q:
⇒ q = 76.8*10⁻⁹ C = 76.8 nC
Becuase the frisbee is spinning at a CONSTANT RATE, the radial acceleration is zero. when radial acceleration is zero, tangential acceleration is zero too, according to the equation Acceleration (tangential) = Acceleration (radial) times radius
The answer to that question is TRUE just had that question last period lol
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<h2>
Answer:</h2>
<em><u>Velocity of throwing arrow = 43.13 m/s.</u></em>
<h2>
Explanation:</h2>
In the question,
Let us say the height from which the arrow was shot = h
Distance traveled by the arrow in horizontal = 61 m
Angle made by the arrow with the ground = 2°
So,
From the <u>equations of the motion</u>,
Now,
Also,
Finally, the angle made is 2 degrees with the horizontal.
So,
Final horizontal velocity = v.cos20°
Final vertical velocity = v.sin20°
Now,
u = v.cos20° (No acceleration in horizontal)
Also,
So,
We can say that,
<em><u>Therefore, the velocity with which the arrow was shot by the archer is 43.13 m/s.</u></em>