What this setup essentially represents is “How many 8s can we take away from 32 before hitting 0?” Which in turn can be reframed as “How many 8s fit into 32?” This can be captured in the expression 32 / 8. As we can see from the problem, we can take away 4 8’s before hitting 0, so that gives us the equation 32 / 8 = 4
Answer: which question
Step-by-step explanation:
Answer:
3000
Step-by-step explanation:
x = original amount of GHC
--> 1/6x = 500
x= 3000
D, because a histogram does not show individual data points
